Hello,
We have a simple/working playbook that looks for log files based on the
server's name and prints the file(s) it could find:
vars:
log_files: "/path/to/directory"
tasks:
- name: Collect log files
ansible.builtin.find:
path: "{{ log_files }}/"
patterns: "*{{ inventory_hostname }}*"
register: log_search
- name: print collection result
ansible.builtin.debug:
msg: "{{ item.path }}"
with_items: "{{ log_search.files }}"
For each file found, the the printout looks like this:
ok: [SERVER_NAME] => (item={'path':
'/path/to/directory/logs/monitor-<SERVER_NAME>-02-2024.03.18.log', 'mode':
'0644',
'isdir': False, 'ischr': False, 'isblk': False, 'isreg': True, 'isfifo':
False, 'islnk': False, 'issock': False, 'uid': 999, 'gid': 999,
'size': 272091, 'inode': 12956486, 'dev': 45, 'nlink': 1, 'atime':
1710905864.848738, 'mtime': 1710827942.815553, 'ctime': 1710827942.815553,
'gr_name': 'xxxxx', 'pw_name': 'xxxxx', 'wusr': True, 'rusr': True,
'xusr': False, 'wgrp': False, 'rgrp': True, 'xgrp': False, 'woth': False,
'roth': True, 'xoth': False, 'isuid': False, 'isgid': False}) => {
"msg":
"/path/to/directory/logs/monitor-<SERVER_NAME>-02-2024.03.18.log"
}
How could I, if even possible, format the printout so it would only show
the whole path to the file, omitting/discarding all the other file
attributes information?
(And please forgive my ignorance...)
Thanks a lot,
Alex
--
[image: Edmonton_sig_RGB_S.jpg]
Alex Wanderley
Application and Infrastructure Analyst II
Server Solutions & Automation
Financial and Corporate Services | Open City and Technology
780-496-4156 Office
780-819-0273 Mobile
City of Edmonton
Century Place, 19th Floor
9803 102A Avenue NW
Edmonton AB, T5J 3A3
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