HI I have the same question a few weeks ago but I now I understand how to calculate
0.0.2.55 = if u convert 567 into binary using calc you will find 1000110111 right. Now what you need to do is put it into 4 octet so the result is 00000000.00000000.00000010.00110111 next step is on each octet you add any bit that equal to 1 so 1st octet all bits are 0 = 0 2nd octet all bits are 0 = 0 3rd octet bit that equal to 1 = 2 4th octet bit that equal to 1 = 55 result is 0.0.2.55 lets take a look another example 1000 we convert to binary = 1111101000 put it into 4 octet = 00000000.00000000.00000011.11101000 add all bit that are 1 = 0.0.3.232 Hope this will help make you understand Cheers On Sun, Nov 1, 2009 at 2:55 AM, Jeremy L. Gaddis <jer...@evilrouters.net>wrote: > 0.0.2.55 == area 567 > 0.0.2.255 == area 767 > > Likely just a typo in the solution. > > -- > Jeremy L. Gaddis > http://evilrouters.net/ > > > On Sat, Oct 31, 2009 at 2:06 PM, Joe Astorino <jastor...@ipexpert.com> > wrote: > > Convert 567 to binary as a 32-bit number. Take that 32 bits and express > it in dotted decimal > > Regards, > > > > Joe Astorino - CCIE #24347 R&S > > Technical Instructor - IPexpert, Inc. > > Cell: +1.586.212.6107 > > Fax: +1.810.454.0130 > > Mailto: jastor...@ipexpert.com > > > > -----Original Message----- > > From: Ahmed Haji Munye <ahmhaj...@yahoo.se> > > Date: Sat, 31 Oct 2009 17:54:09 > > To: CC IE<ccie_rs@onlinestudylist.com> > > Subject: [OSL | CCIE_RS] Configure VLANS 2567 and 567 to be in area 567. > DO > > not use are 567 in any commands > > > > _______________________________________________ > > For more information regarding industry leading CCIE Lab training, please > visit www.ipexpert.com > > > > > > _______________________________________________ > > For more information regarding industry leading CCIE Lab training, please > visit www.ipexpert.com > > > > > > -- > Jeremy L. Gaddis > http://evilrouters.net/ > _______________________________________________ > For more information regarding industry leading CCIE Lab training, please > visit www.ipexpert.com >
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