It ran without error, but the results returned were wrong. There are 7,768 records in properties and 7,758 records in properties_copy. (because I deleted 10 records to have differences for results to show)
The query below actually returns 9,999 records. The result set should only be the 10 missing records present in properties_copy that are not in properties. -----Original Message----- From: Jason Fisher [mailto:ja...@wanax.com] Sent: Sunday, October 03, 2010 3:39 PM To: cf-talk Subject: Re: Can't figure out a query to accomplish this... Can't you just do this? SELECT p.mls_number FROM properties p LEFT OUTER JOIN properties_copy pc ON p.mls = pc.mls WHERE pc.mls IS NULL AND p.mls = 'hmls' (wouldn't need this bit unless you really only want the 'hmls' records) On 10/3/2010 3:12 PM, Rick Faircloth wrote: > select p.mls_number > from properties p > where p.mls = 'hmls' > and p.mls_number not in (select pc.mls_number from properties_copy pc > where pc.mls = 'hmls') ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~| Order the Adobe Coldfusion Anthology now! http://www.amazon.com/Adobe-Coldfusion-Anthology-Michael-Dinowitz/dp/1430272155/?tag=houseoffusion Archive: http://www.houseoffusion.com/groups/cf-talk/message.cfm/messageid:337801 Subscription: http://www.houseoffusion.com/groups/cf-talk/subscribe.cfm Unsubscribe: http://www.houseoffusion.com/groups/cf-talk/unsubscribe.cfm
