On Tue, Mar 08, 2016 at 11:43:53AM +0800, ychen wrote:
>   I noticed that when add or delete port, the transaction always send op wait 
> with all the ports in the same bridge.
>  If the port p0 and p1 are totally independent, and have no relationship with 
> each other, why when I add port p1, I need to wait port p0?

This implements transactional atomicity.  If two transactions each add a
different port, and they execute at the same time, one of them needs to
fail and be retried, otherwise only one of the ports will be added in
the end.
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