Thanks, Jeff. It’s not choose some columns of a Row. It’s just choose all data 
in a column and convert it to an Array. Do you understand my mean ?

In Chinese
我是想基于这个列名把这一列中的所有数据都选出来,然后放到数组里面去。


发件人: Jeff Zhang [mailto:zjf...@gmail.com]
发送时间: 2015年12月25日 15:39
收件人: zml张明磊
抄送: dev@spark.apache.org
主题: Re: How can I get the column data based on specific column name and then 
stored these data in array or list ?

Not sure what you mean. Do you want to choose some columns of a Row and convert 
it to an Arrray ?

On Fri, Dec 25, 2015 at 3:35 PM, zml张明磊 
<mingleizh...@ctrip.com<mailto:mingleizh...@ctrip.com>> wrote:

Hi,

       I am a new to Scala and Spark and trying to find relative API in 
DataFrame to solve my problem as title described. However, I just only find 
this API DataFrame.col(colName : String) : Column which returns an object of 
Column. Not the content. If only DataFrame support such API which like 
Column.toArray : Type is enough for me. But now, it doesn’t. How can I do can 
achieve this function ?

Thanks,
Minglei.



--
Best Regards

Jeff Zhang

Reply via email to