Thanks, Jeff. It’s not choose some columns of a Row. It’s just choose all data in a column and convert it to an Array. Do you understand my mean ?
In Chinese 我是想基于这个列名把这一列中的所有数据都选出来,然后放到数组里面去。 发件人: Jeff Zhang [mailto:zjf...@gmail.com] 发送时间: 2015年12月25日 15:39 收件人: zml张明磊 抄送: dev@spark.apache.org 主题: Re: How can I get the column data based on specific column name and then stored these data in array or list ? Not sure what you mean. Do you want to choose some columns of a Row and convert it to an Arrray ? On Fri, Dec 25, 2015 at 3:35 PM, zml张明磊 <mingleizh...@ctrip.com<mailto:mingleizh...@ctrip.com>> wrote: Hi, I am a new to Scala and Spark and trying to find relative API in DataFrame to solve my problem as title described. However, I just only find this API DataFrame.col(colName : String) : Column which returns an object of Column. Not the content. If only DataFrame support such API which like Column.toArray : Type is enough for me. But now, it doesn’t. How can I do can achieve this function ? Thanks, Minglei. -- Best Regards Jeff Zhang