Adithya Kumar <adi.obilise...@gmail.com> writes: > Hello all, > > I have a use-case where I want to convert `ByteArray#` to > `MutableByteArray#` > without the copy overhead. > > Is the underlying memory structure of `ByteArray#` and `MutableByteArray#` > the same? > > If I can guarantee that I won't mutate my `MutableByteArray#`, can I use > `unsafeCoerce#` on `ByteArray#` and treat it as `MutableByteArray#`? > Note that a future release of GHC (IIRC 9.10) will have a (no-op) operation for precisely this purpose. See [1].
Cheers, - Ben [1] https://gitlab.haskell.org/ghc/ghc/-/issues/22710 _______________________________________________ ghc-devs mailing list ghc-devs@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/ghc-devs
