Admittedly, C and Python work the same way, which is different to Go.
#include <stdio.h>
int main(void) {
printf("%07x\n", 42);
printf("%0#7x\n", 42);
printf("0x%07x\n", 42);
return 0;
}
// Output
000002a
0x0002a
0x000002a
On Wednesday 31 January 2024 at 13:56:07 UTC Brian Candler wrote:
> https://pkg.go.dev/fmt#hdr-Printing
>
> The '#' means you want the alternate format with the 0x prepended, and the
> '7' means you want the number itself padded to 7 digits
>
> x := fmt.Sprintf("%07x", 42) // 000002a
> y := fmt.Sprintf("%0#7x", 42) // 0x000002a
> z := fmt.Sprintf("0x%07x", 42) // 0x000002a
>
> Seems pretty logical to me. If Python chooses to do it a different way,
> that's because Python is a different language.
>
> On Wednesday 31 January 2024 at 13:23:01 UTC Lukas Toral wrote:
>
>> Hello,
>>
>> I am working on code that formats strings. I have an issue with
>> formatting the alternate form with zero padding of signed hexadecimals.
>>
>> I have a format string like this: "%#07x", I would expect the zero
>> padding to make sure the total width is 7. However, when I format the
>> string using fmt.Sprintf I get the following results: 0x000002a which has
>> the length of 9 characters instead of the expected result: 0x0002a with the
>> width of 7 characters.
>>
>> Example code: x := fmt.Sprintf("%#07x", 42)
>> x will be equal to: 0x000002a
>>
>> Example of python code that works as I would expect: result =
>> "{:#07x}".format(42)
>> results will be equal to: 0x0002a
>>
>> I am suspicious that this might be a bug where the 0x is not accounted in
>> the width but maybe I am doing something wrong.
>> Thanks for any help :)
>>
>
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