It is not 4 bytes, it is just that the following field is full word aligned. If the following field were FL4 rather than F, you will see the alignment change. I think there is an option to turn off alignment, but don't remember ever using it.
-----Original Message----- From: IBM Mainframe Discussion List [mailto:IBM-MAIN@LISTSERV.UA.EDU] On Behalf Of Nguyen Dt Sent: Saturday, July 4, 2020 8:48 PM To: IBM-MAIN@LISTSERV.UA.EDU Subject: Assembler question Dear lister, I am learning assembler on my own, i have something strange that i can't explain , please help me to understand Here is a section of my code : 608 DBLWORD DS D DBLE WORD 609 PATTERN6 DC X'402020202120' 610 * 611 REPORTO7 DS 0CL274 612 OW0007DB DS XL2 613 OW0007OB DS XL2 614 OW0007AC DS F 615 OW0007NP DS H 616 OW0007PT DS F 617 OW0007PF DS CL256 618 * And here is the listing at compilation 0007FE 611 REPORTO7 DS 0CL274 0007FE 612 OW0007DB DS XL2 000800 613 OW0007OB DS XL2 000804 614 OW0007AC DS F 000808 615 OW0007NP DS H 00080C 616 OW0007PT DS F I don't undestand why OW0007OB is 2 bytes , but on the left it is considered as 4 bytes long , the same for QW0007NP I read something with alignment obut it seems to concern constants , and this is not constant ? Thank you for clarification ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN -- This e-mail message has been scanned and cleared by Google Message Security and the UNICOM Global security systems. This message is for the named person's use only. If you receive this message in error, please delete it and notify the sender. ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN
