If you want a really simple example:
function test(o) {
var defaults = {
test: ''
};
for(var k in o){
defaults[k] = o[k];
}
alert(defaults.test);
}
test({test: 'It works!'});
(nb. also assigns new properties to 'defaults')
On Jun 24, 5:16 pm, Nic Hubbard <nnhubb...@gmail.com> wrote:
> How does jQuery do it for plugins? I was wanting to be able to use
> callbacks as well in the object.
>
> What is happening what a plugin uses: var options = $.extend(defaults,
> options);
>
> Somehow, that is getting the object to pass through as the function
> params.
>
> Any help on this?
>
> On Jun 24, 12:09 am, fredrik <carl.fredrik.bonan...@gmail.com> wrote:
>
>
>
> > Not really sure what you are after. But I think you need to make an
> > new instance of test first:
>
> > var test = function (defaults){
> > this.defaults = defaults || this.defaults;
> > alert(this.defaults.test);
>
> > }
>
> > test.prototype = {
> > defaults : { test : 'nothing' }
>
> > };
>
> > new test();
> > new test({test: 'hello world'});
>
> > On Jun 24, 8:07 am, Nic Hubbard <nnhubb...@gmail.com> wrote:
>
> > > I have used an object in the past as a function argument, but this was
> > > for a plugin that I wrote. Using it in the architecture of a plugin
> > > it worked.
>
> > > BUT, this time, I just want to write a normal function, but still use
> > > an object to set defaults and pass in changes to those defaults
> > > through as a param. Is this possible, or do I have to make this a
> > > jQuery function like $.myfunction() ?
>
> > > I am trying:
>
> > > function test(defaults)
> > > {
> > > var defaults = {
> > > test: ''
> > > };
>
> > > alert(defaults.test);
>
> > > }
>
> > > test({test: 'It works!'});
>
> > > The above does not seem to work, and replace the default with that was
> > > passed in the function. What am I doing wrong here?
