>I did not know about eq and I don't have all fing day to figure this

http://docs.jquery.com/Core/index
http://docs.jquery.com/Traversing/eq

Most everything you will need is in the docs. It's worth spending some
time studying them.


On Jul 9, 11:52 am, expresso <dschin...@gmail.com> wrote:
> I did not know about eq and I don't have all fing day to figure this
> out as I am very new to jQuery.  I do my dilligence and read the
> books, try some stuff out and then when I am not sure of another way
> to do this I post.  It's not like I am posting every step of the way
> although it msut appear that to you.  I tried a few things before I
> posted.
>
> On Jul 9, 7:04 am, Charlie <charlie...@gmail.com> wrote:
>
>
>
> > of course it won't work, is improper use of index(),
> > replace index() with eq()
> > Suggestion:
> > instead of posting each and every thought and failed function you have 
> > every 2 minutes, this example could have been created in a very simple test 
> > page to get the methods and syntax sorted out. Would have saved us watch 
> > the floundering on each and every step of your grief. Other example you 
> > tried $("#mycarousel > li[" + i + "]") is syntax problem with several 
> > workarounds including :eq()
> > Building simple test pages is one of the best ways to learn jquery IMO. 
> > Keeping a simple template including link to jquery google source, and a 
> > $(document)ready built in you can build a test page in any directory in 
> > almost no time and debug in Firebug
> > expresso wrote:tried this but doesn't look like you can do this 
> > $("#mycarousel > li").index(i).css("margin-right", "0px").css("padding- 
> > right", "6px"); On Jul 8, 9:48 pm, expresso<dschin...@gmail.com>wrote:Like 
> > something like this $("#mycarousel > li[" + i + "]").css("margin-right", 
> > "0px").css ("padding-right", "6px"); On Jul 8, 9:46 pm, 
> > expresso<dschin...@gmail.com>wrote:Thanks.  I wonder if you can even access 
> > an <li> by index?On Jul 8, 9:35 pm, MorningZ<morni...@gmail.com>wrote:Why 
> > wouldn't you just use:http://docs.jquery.com/Selectors/last$("#mycarousel > 
> > li:last").css("property", "value");On Jul 8, 10:17 pm, 
> > expresso<dschin...@gmail.com>wrote:If I have the following:<div 
> > class="jcarousel-clip jcarousel-clip-horizontal" style="width: 459px; 
> > height: 220px;">     <ul id="mycarousel" class="jcarousel-list 
> > jcarousel-list- horizontal" style="height: 220px; width: 918px; left: 
> > 0px;">         <li class="jcarousel-item jcarousel-item-horizontal 
> > jcarousel- item-1 jcarousel-item-1-horizontal" jcarouselindex="1">         
> > </li>         <li class="jcarousel-item jcarousel-item-horizontal 
> > jcarousel- item-2 jcarousel-item-2-horizontal" jcarouselindex="2">         
> > </li>         <li class="jcarousel-item jcarousel-item-horizontal 
> > jcarousel- item-3 jcarousel-item-3-horizontal" jcarouselindex="3">         
> > </li> </ul> </div>Trying to figure out how I can do a .each on each <li> 
> > and then add an additional style to the last <li> in the list.

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