Hi Laurent

On 18/12/2020 16:02, Laurent Pinchart wrote:
> Hi Daniel,
> 
> Thank you for the patch.
> 
> On Thu, Dec 17, 2020 at 11:43:29PM +0000, Daniel Scally wrote:
>> Registering software_nodes with the .parent member set to point to a
>> currently unregistered software_node has the potential for problems,
>> so enforce parent -> child ordering in arrays passed in to
>> software_node_register_nodes().
>>
>> Software nodes that are children of another software node should be
>> unregistered before their parent. To allow easy unregistering of an array
>> of software_nodes ordered parent to child, reverse the order in which
>> software_node_unregister_nodes() unregisters software_nodes.
>>
>> Suggested-by: Andy Shevchenko <andriy.shevche...@linux.intel.com>
>> Signed-off-by: Daniel Scally <djrsca...@gmail.com>
>> ---
>> Changes in v2:
>>
>>      - Squashed the patches that originally touched these separately
>>      - Updated documentation
>>
>>  drivers/base/swnode.c | 43 ++++++++++++++++++++++++++++++-------------
>>  1 file changed, 30 insertions(+), 13 deletions(-)
>>
>> diff --git a/drivers/base/swnode.c b/drivers/base/swnode.c
>> index 615a0c93e116..cfd1faea48a7 100644
>> --- a/drivers/base/swnode.c
>> +++ b/drivers/base/swnode.c
>> @@ -692,7 +692,10 @@ swnode_register(const struct software_node *node, 
>> struct swnode *parent,
>>   * software_node_register_nodes - Register an array of software nodes
>>   * @nodes: Zero terminated array of software nodes to be registered
>>   *
>> - * Register multiple software nodes at once.
>> + * Register multiple software nodes at once. If any node in the array
>> + * has it's .parent pointer set, then it's parent **must** have been
>> + * registered before it is; either outside of this function or by
>> + * ordering the array such that parent comes before child.
>>   */
>>  int software_node_register_nodes(const struct software_node *nodes)
>>  {
>> @@ -700,33 +703,47 @@ int software_node_register_nodes(const struct 
>> software_node *nodes)
>>      int i;
>>  
>>      for (i = 0; nodes[i].name; i++) {
>> -            ret = software_node_register(&nodes[i]);
>> -            if (ret) {
>> -                    software_node_unregister_nodes(nodes);
>> -                    return ret;
>> +            const struct software_node *parent = nodes[i].parent;
>> +
>> +            if (parent && !software_node_to_swnode(parent)) {
>> +                    ret = -EINVAL;
>> +                    goto err_unregister_nodes;
>>              }
>> +
>> +            ret = software_node_register(&nodes[i]);
>> +            if (ret)
>> +                    goto err_unregister_nodes;
>>      }
>>  
>>      return 0;
>> +
>> +err_unregister_nodes:
>> +    software_node_unregister_nodes(nodes);
>> +    return ret;
>>  }
>>  EXPORT_SYMBOL_GPL(software_node_register_nodes);
>>  
>>  /**
>>   * software_node_unregister_nodes - Unregister an array of software nodes
>> - * @nodes: Zero terminated array of software nodes to be unregistered
>> + * @nodes: Zero terminated array of software nodes to be unregistered.
> 
> Not sure if this is needed.

Hah, of course. Hangover from the last version (when I had made that
line two sentences)
> 
>>   *
>> - * Unregister multiple software nodes at once.
>> + * Unregister multiple software nodes at once. If parent pointers are set up
>> + * in any of the software nodes then the array MUST be ordered such that
> 
> I'd either replace **must** above with MUST, or use **must** here. I'm
> not sure if kerneldoc handles emphasis with **must**, if it does that
> seems a bit nicer to me, but it's really up to you.

Honestly I haven't delved into kerneldoc yet, but either way I think
**must** is better in both places - will change.

> Reviewed-by: Laurent Pinchart <laurent.pinch...@ideasonboard.com>

Thank you!
> 
>> + * parents come before their children.
>>   *
>> - * NOTE: Be careful using this call if the nodes had parent pointers set up 
>> in
>> - * them before registering.  If so, it is wiser to remove the nodes
>> - * individually, in the correct order (child before parent) instead of 
>> relying
>> - * on the sequential order of the list of nodes in the array.
>> + * NOTE: If you are uncertain whether the array is ordered such that
>> + * parents will be unregistered before their children, it is wiser to
>> + * remove the nodes individually, in the correct order (child before
>> + * parent).
>>   */
>>  void software_node_unregister_nodes(const struct software_node *nodes)
>>  {
>> -    int i;
>> +    unsigned int i = 0;
>> +
>> +    while (nodes[i].name)
>> +            i++;
>>  
>> -    for (i = 0; nodes[i].name; i++)
>> +    while (i--)
>>              software_node_unregister(&nodes[i]);
>>  }
>>  EXPORT_SYMBOL_GPL(software_node_unregister_nodes);
> 

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