Fixed in https://github.com/metamath/metamath-website-seed/pull/20.

On Sun, Nov 12, 2023 at 4:18 AM Mario Carneiro <di.g...@gmail.com> wrote:

> Looks like this is because the source was line-broken there, it says
>
> <IMGSRC='leftrightarrow.gif' WIDTH=15 HEIGHT=19 ALT='&lt;-&gt;'>
>
> in the source and this is enough to fool the simple image usage heuristic
> here:
>
>
> https://github.com/metamath/metamath-website-scripts/blob/8d81a0c1ab3e433b335b4e6a3bdc364d277b4946/build-website.sh#L133
>
> I'm not sure what the best alternative is. Perhaps the easiest thing would
> be to just make those non-breaking points and make sure that there are no
> such breaks in any of the other files...
>
> On Sat, Nov 11, 2023 at 9:48 AM Gino Giotto <ginogiotto.giap...@gmail.com>
> wrote:
>
>> On the https://us.metamath.org/mmsolitaire/mms.html webpage, when it
>> says  " [image: <->] (double arrow): logically equivalent to" there
>> seems to be a missing picture.
>>
>> Il giorno domenica 29 ottobre 2023 alle 03:46:02 UTC+1 di....@gmail.com
>> ha scritto:
>>
>>> On Wed, Oct 25, 2023 at 3:46 PM Gino Giotto <ginogiott...@gmail.com>
>>> wrote:
>>>
>>>> From https://us.metamath.org/copyright.html#pd the GNU General Public
>>>> License <https://us.metamath.org/LICENSE.TXT> link gives a 404.
>>>
>>>
>>> The top level LICENSE.TXT has been removed, as the web site is PD not
>>> GPLv2 (except for some enumerated exceptions) and this positioning of the
>>> license was misleading. The script used to copy this LICENSE.TXT into
>>> mmsolitaire/ and metamath/, but metamath/ is now being handled separately
>>> (the metamath-exe repo) and mmsolitaire already has this file, so the
>>> copies are no longer necessary. I think it would make the most sense to
>>> just point to
>>> https://www.gnu.org/licenses/old-licenses/gpl-2.0.en.html#SEC1 in that
>>> link rather than use a local copy.
>>>
>> --
>> You received this message because you are subscribed to the Google Groups
>> "Metamath" group.
>> To unsubscribe from this group and stop receiving emails from it, send an
>> email to metamath+unsubscr...@googlegroups.com.
>> To view this discussion on the web visit
>> https://groups.google.com/d/msgid/metamath/ee5cb20c-ab52-4d2b-9b4b-ab67bf0c27fdn%40googlegroups.com
>> <https://groups.google.com/d/msgid/metamath/ee5cb20c-ab52-4d2b-9b4b-ab67bf0c27fdn%40googlegroups.com?utm_medium=email&utm_source=footer>
>> .
>>
>

-- 
You received this message because you are subscribed to the Google Groups 
"Metamath" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to metamath+unsubscr...@googlegroups.com.
To view this discussion on the web visit 
https://groups.google.com/d/msgid/metamath/CAFXXJStY0XcawRZ3RBkuvmyaRbPMZSPnfkzwD5L56E5BPoR%3DEA%40mail.gmail.com.

Reply via email to