Dear Sietse,
Thanks a lot!!!
> Finally found it, after lots of trial-and-erroring through
> likely-looking table names in file-job.lua: the stack of input files
> is kept in resolvers.inputstack.
I don't program any "lua". But I was taking a look at "file-job.lua"
myself. I have a lot to learn!! :-)
> Assuming (absolute path of invocation
> dir) + (path of file relative to invocation dir) = the desired path,
I don't mind this assumption.
Actually, I don't mind having a path relative to the currdir.
> the following should work.
>
> \cldcontext{
> environment.runpath .. '/' ..
> file.pathpart(resolvers.inputstack[#resolvers.inputstack])
> }
I will try this now.
> You may or may not want to parse out any ./ and ../ components.
No, I don't need that.
> (If you do: helpful filename manipulation functions (such as
> file.pathpart, indeed) may be found in l-file.lua.)
Thanks for the tip. Might be useful someday.
> Hope this helps,
It does! :-)
Although, I think there should be a "luatex" command for this. That
is, something not related to ConTeXt.
Thank you,
André Caldas.
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