to find out if an array is empty use:
empty()

it must be unset
NULL returns false
0 returns false
it must be truly empty to return true...



> Ok... well
> 
> When I select the "select product" which has a option value="" it tells
> me the count is one (1). If I select an ACTUAL product it tells me
> one(1) was select.. if I select two ACTUAL products it tells me two (2)
> products were selected.
> 
> For SOME reason it doesn't seem to be recognizing that the option
> value="" is empty!
> 
> 
> Any more ideas??????
> 
> *sigh*
> 
> Aaron
> 
> -----Original Message-----
> From: Hutchins, Richard [mailto:[EMAIL PROTECTED]]
> Sent: February 5, 2003 4:03 PM
> To: 'Aaron Wolski'; [EMAIL PROTECTED]
> Subject: RE: [PHP-DB] checking for empty array from a form field?
> grrrrrrrrrrr!
> 
> What about:
> 
> count($arrayname)
> 
> Should tell you how many items are in an array.
> 
> > -----Original Message-----
> > From: Aaron Wolski [mailto:[EMAIL PROTECTED]]
> > Sent: Wednesday, February 05, 2003 4:04 PM
> > To: [EMAIL PROTECTED]
> > Subject: [PHP-DB] checking for empty array from a form field?
> > grrrrrrrrrrr!
> >
> >
> > Argh !!!!!!!!
> >
> >
> > HOW does one check for an array being empty from a form
> > field??????????
> >
> > Tried a billion different things and NOTHING works!!!!
> >
> > I've tried:
> >
> > if ($products == "\n") {
> >
> > echo "hello";
> > }
> >
> > else {
> >
> >             echo "bye";
> >
> > }
> >
> >
> > if ($products == "") {
> >
> > echo "hello";
> > }
> >
> > else {
> >
> >             echo "bye";
> >
> > }
> >
> >
> >
> > if (empty($products)) {
> >
> > echo "hello";
> > }
> >
> > else {
> >
> >             echo "bye";
> >
> > }
> >
> >
> > if (!isset($products)) {
> >
> > echo "hello";
> > }
> >
> > else {
> >
> >             echo "bye";
> >
> > }
> >
> >
> > if (count($products) == 0) {
> >
> > echo "hello";
> > }
> >
> > else {
> >
> >             echo "bye";
> >
> > }
> >
> >
> > NOTHING works!!!
> >
> > Any help.. puuulease?
> >
> > Aaron
> >
> 
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> 
> 
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