Bostjan Skufca @ domenca.com wrote:
function add ($a=1, $b=2, $c=3) {
return $a + $b + $c;
}
add(1, null, 1);
will do just fine
returns 2, OP wants 4 IMO
r.,
Bostjan
On Thursday 28 April 2005 14:16, Marek Kilimajer wrote:
Vedanta Barooah wrote:
Hello All,
Cosider this :
function add($a=1,$b=2,$c=3){
return $a + $b + $c;
}
how do i skip the second argument while calling the function, is there
a process like this:
echo add(1,,1); # where i expect 2 to be printed,
php does not support this. you can workaround this using:
function add($a = null,$b = null, $c = null){
if(is_null($a)) $a = 1;
if(is_null($b)) $b = 2;
if(is_null($c)) $c = 3;
return $a + $b + $c;
}
add(1, null, 1);
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