print preg_replace('/^(.*?)([a-zA-Z]{2})(.*)/','\\2',$blah);
try that
-jack
"scott [gts]" wrote:
>
> oh yeah. sorry...
>
> > -----Original Message-----
> > From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of Jack
> > Dempsey
> > Sent: Thursday, May 10, 2001 3:15 PM
> > To: ..s.c.o.t.t.. [gts]
> > Cc: Php-General
> > Subject: Re: [PHP] ereg issues
> >
> >
> > isn't a \w a word character, meaning a-zA-Z_0-9 (in perl)?
> > if so, that wouldn't match the a-zA-z he originally intended...
> > am i missing something?
> >
> > -jack
> >
> > "..s.c.o.t.t.. [gts]" wrote:
> > >
> > > print preg_replace('/(.*?)(\w{2})(.*)/', '\\2', $blah);
> > >
> > > works for:
> > >
> > > $blah = "*9 scott 777zxsdf";
> > > and
> > > $blah = "scott";
> > >
> > > > -----Original Message-----
> > > > From: Jerry Lake [mailto:[EMAIL PROTECTED]]
> > > > Subject: [PHP] ereg issues
> > > >
> > > > I'm feeling a bit stupid today
> > > > how do I truncate a string to the
> > > > first two [a-zA-Z] characters ?
> > > >
> > > > this sure isn't working
> > > > <snip>
> > > > $test = "jerry";
> > > > $test = ereg_replace("^\w*", "^[a-zA-Z]{2}" ,$test);
> > > > </snip>
> > >
> > > --
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