Thats great thanks, but it doesn't solve my problem completly, im trying to use $output = $var(); .. which gives me an error. The $var(); works though, so thanks for that.
Robert Keizer ""Robert Keizer"" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] >I am currently working on a module testing class, I can't seem to find the >correct syntax. Here is an example of the problem: > > function foo( $var ){ > include $var.'.php'; > return $var(); // <!------- problem > }; > > foo("somefunction"); > > In other words I am looking for a way to call a function by the value of a > variable. I get a Call to undefined method error, > any help would be great.. > > -- > [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
