You wrote:
> I am trying to receive file names but can't quite figure out the
proper > substr to do it:
>
> jeff.dat
> jeffrey.dat
> chris.dat
> tom.dat
>
> I want to receive the name to the left of the .dat
>
> Jeff
$file = array("jeff.dat", "jeffrey.dat", "chris.dat", "tom.dat");
for($i=0; $i<count($file); $i++){
eregi("^(.*)\.dat$", $file[$i], $ary);
$filename = $ary[1];
// Do something with $filename
print "$filename<br>\n";
}
HTH! :)
--
-Ryan :: ICQ - 595003 :: GigaBoard - http://www.gigaboard.net/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
