Hmmm, RegEx work on strings, so the engine needs strings. Because of that your
integers are converted to strings, if you want to
give their life back make
foreach ($arr as $k=>$v){
$arr[$k]+=0;
}
Now all are integers.
Andrey Hristov
IcyGEN Corporation
http://www.icygen.com
BALANCED SOLUTIONS
----- Original Message -----
From: "Nicolas Guilhot" <[EMAIL PROTECTED]>
To: "Php General MailingList" <[EMAIL PROTECTED]>
Sent: Tuesday, September 11, 2001 3:24 PM
Subject: [PHP] preg_replace is modifying the type of replacement parameter !!
> Hi guys,
>
> When I use preg_replace with an array of integer as the replacement
> parameter, this function modifies the type of each array element to string.
> I don't understand why it alters the content of the array while this
> variable is not pass by reference (True or not ??).
>
> I have just upgraded to PHP 4.0.6 and it I don't think it was the case in
> PHP 4.0.4 (the version I was using before, without this problem).
>
> Here is a short example that demonstrate my problem.
>
> <?php
> $ary_pattern = array("@One@");
> $ary_replace = array(1);
> $string_before = "One example";
> echo gettype($ary_replace[0]); // This line outputs 'integer'
> $string_after = preg_replace($ary_pattern, $ary_replace, $string_before);
> echo "<br>$string_after<br>";
> echo gettype($ary_replace[0]); // This line outputs 'string'
> ?>
>
> Is this a bug from preg_replace or am I doing wrong somewhere? Any help
> would be appreciated.
> Regards.
>
> Nicolas Guilhot
>
>
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