maybe you forgot something like:
.....
$letter=26-(ord($word[$i])-65); // excellent !!!
if (($letter<1)||($letter>26))
$letter=0;
$total+=$letter;
....
(°- Nayco,
//\ [EMAIL PROTECTED]
v_/_ http://nayco.free.fr
----- Original Message -----
From: David Otton <[EMAIL PROTECTED]>
To: Ralph Guzman <[EMAIL PROTECTED]>
Cc: PHP General Mailing List <[EMAIL PROTECTED]>
Sent: Tuesday, September 11, 2001 2:32 PM
Subject: Re: [PHP] Anagram Solution in PHP
> On Mon, 10 Sep 2001 01:25:36 -0700, you wrote:
>
> >So let's say the word 'acronym'
> >
> >A + C + R + 0 + N + Y + M
> >26 + 24 + 9 + 12 + 13 + 2 + 14 = 100
> >
> >My thoughts were to download a list of words in the dictionary, then read
> >the file and somehow replace each letter by its number, then add each
letter
> >for each word and see which words would equal to 100.
> >
> >So I am emailing this list for any suggestions or examples of code that I
> >can use to accomplish this. Any help?
>
> function total ($word) {
> $total = 0;
> $word = strtoupper($word);
> for ($i=0; $i<strlen($word); $i++) {
> $total+=26-(ord($word[$i])-65);
> }
> return($total);
> }
>
> echo total('acronym');
>
> djo
>
>
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