Hy,


universal2001 wrote:

> Hi again!
> 
> Thanks for the reply!
> 
> I still have another question:

> 
> so I tired to use (echo) like this:
> 
> echo "<table border="0" cellpadding="0" cellspacing="0" width="639">
>   <tr>
>     <td><img src="img_heading/spacer.gif" width="25" height="1"
> border="0"></td>
>   </tr>
>   <tr>
>     <td colspan="11"><img name="index_r1_c1"
> src="img_heading/index_r1_c1.gif" width="639" height="5" border="0"></td>
>     <td><img src="img_heading/spacer.gif" width="1" height="5"
> border="0"></td>
>   </tr>
>   <tr>
>     <td rowspan="5"><img name="index_r2_c1"
> src="img_heading/index_r2_c1.gif" width="25" height="43" border="0"></td>
> </table>";
> but it DOES NOT WORK.
> How do I get way with all of the quotation marks????




1) you can escape each double quote with a backslash,
the first line of your thing woulkd then look like

echo "<table border=\"0\" cellpadding=\"0\" cellspacing=\"0\" width=\"639\">

and so on

2) if you don't want this by any reason, you can use single quotes to 
mark the text you want to print out like in

echo '<table width="100%">';

the difference is that with single quotes you will _not_ be able to use 
variable replacement in between the quotes, something like

<?
$myvar=100;
echo "<table width=\"$myvar\">";
?>

will output

<table width="100%">


while this:

<?
$myvar=100;
echo '<table width="$myvar">';
?>

will output exactly

<table width="$myvar">


hth,
henning



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