Well, it sounds like something that could be done through the db query, but if you want to use arrays, it'd be something like this...
$servers = arrray('s1','s2','s3','s4','s5'); $group1 = array('s1','s4','s5'); $in_group = array_intersect($servers, $group1); $not_in_group = array_diff($servers, $group1); mh. On Wed, 5 Jun 2002, Chris Knipe wrote: > hey everyone, > > Does anyone have and ideas of wisdom on how to compare arrays (mysql result > sets) and group items based on if they exist in two or more arrays? > > For example: > > I have a table, with a list of servers: > server1 > server2 > server3 > server4 > server5 > ... > serverX > > I have a table that specifies which of the servers are grouped: > group1 > server1 > server4 > server5 > > Now, I want to compare group1 against the server list, and do something like > the following: > In group: > server1 > server4 > server5 > > Not in group: > server2 > server3 > serverX -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php