So Jason what your saying is this $query = "INSERT INTO contacts (id, name, pass, email, dateAdded) VALUES > (NULL, '$name', '$pass', '$email', '$time')"; Should be
$query = "INSERT INTO contacts (id, name, pass, email, dateAdded) VALUES > (NULL, '$name', '$pass', '$email', NOW())"; ?? cheers "Jason Wong" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > On Tuesday 07 January 2003 00:19, - \[ Paul Ferrie \] - wrote: > > hey guys could someone help me > > I have created a user login register system in flash with PHP and Mysql. > > Everthing Now works fine aprt from the time stamp of when the user > > registered. > > > > Code ----------------------------------- > > // Get current date & time > > $time = time(); > > // Connects to the Database. > > $Connect = mysql_connect($dbServer, $dbUser, $dbPass); > > mysql_select_db("$dbName"); > > // Preforms the SQL query to see if user name already exsists > > $query = "SELECT name FROM contacts WHERE name='$name'"; > > $rs_contacts = mysql_query($query) or die(mysql_error()); > > $row = mysql_fetch_assoc($rs_contacts); > > if ($row[name] == $name) { > > print "loginT=UserName in Use&checklog=2"; > > }else{ > > $query = "INSERT INTO contacts (id, name, pass, email, dateAdded) VALUES > > (NULL, '$name', '$pass', '$email', '$time')"; > > } > > > > > > It inserts 0000-00-00 > > instead of the current date > > What column type is dateAdded? If it's a mysql DATE type then you should > > replace: > > '$time' > > with > > NOW() > > -- > Jason Wong -> Gremlins Associates -> www.gremlins.biz > Open Source Software Systems Integrators > * Web Design & Hosting * Internet & Intranet Applications Development * > > /* > It's more than magnificent -- it's mediocre. > -- Sam Goldwyn > */ > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
