Ethan Furman added the comment:

http://stackoverflow.com/q/1408171/208880

No, it just says (towards the top):
----------------------------------
> One important thing that everybody seems to neglect to mention is that writing
> threadLocal = threading.local() at the global level is required. Calling
> threading.local() within the worker function will not work.

It is now my experience that "will not work" (reliably) is accurate.

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<http://bugs.python.org/issue24020>
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