Ivan Levkivskyi <levkivs...@gmail.com> added the comment: > Remind me what happens when you use `await` in a generator expression that > survives the async function's scope?
Awaiting on f([1, 2]) will result in an async generator (even though yield never appears here). Yury explained why this happens in https://bugs.python.org/issue32113 ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue10544> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
