New submission from Paul Ganssle <[email protected]>:
In a recent python-dev thread, there was some confusion about how to get
something like `timedelta.total_microseconds()`. There is already an existing,
supported idiom for this, which is that `timedelta` implements division:
td = timedelta(hours=1)
num_microseconds = td / timedelta(microseconds=1)
In this e-mail (
https://mail.python.org/pipermail/python-dev/2019-February/156351.html ), Nick
Coghlan proposed that we update the documentation and there were no objections,
quoting:
* In the "Supported Operations" section of
https://docs.python.org/3/library/datetime.html#timedelta-objects,
change "Division (3) of t2 by t3." to "Division (3) of overall
duration t2 by interval unit t3."
* In the total_seconds() documentation, add a sentence "For interval units
other than seconds, use the division form directly (e.g. `td /
timedelta(microseconds=1)`)"
I am starting this issue to track that change.
----------
assignee: docs@python
components: Documentation, Library (Lib)
messages: 336765
nosy: belopolsky, docs@python, ncoghlan, p-ganssle
priority: normal
severity: normal
status: open
title: Improve documentation about converting datetime.timedelta to scalars
versions: Python 3.7, Python 3.8
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<https://bugs.python.org/issue36138>
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