Jeroen Demeyer <j.deme...@ugent.be> added the comment:

> but it will make d1.update(**d2) slower with a complexity of O(n): d2 must be 
> converted to 2 lists

This part is still true and it causes a slow-down of about 23% for 
dict.update(**d), see benchmarks at 
https://github.com/python/cpython/pull/14589#issuecomment-509356084

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