Quentin Peter <qpe...@bluewin.ch> added the comment:
The reason I am asking is that I am working on a debugger. The debugger stops
on a frame which is inside a function. Let's say the locals is:
locals() == {"a": 1}
I now want to define a closure with exec. I might want to do something like:
exec("def f(): return a", globals(), locals())
But this doesn't work because of the issue I describe.I would expect f() to
look for a in the locals().
Even more surprising is that if I use the second argument of exec, the code in
the above comment starts to fail.
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue46153>
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