On Sep 7, 2011, at 6:04 AM, Varsha Agrawal wrote:
The code looks like this:
L1=list(a=1,b=2,c=3)
f1=as.factor(c)
L1[[f1]] returns 1
What happens if we give a factor as an index at a list?
In a virgin session of R there would be no 'c' for the second line to
work with. And since 'c' is a function you would probably get an error.
> L1=list(a=1,b=2,c=3)
> f1=as.factor(L1$c)
> f1
[1] 3
Levels: 3
> L1[[f1]] #returns 1
[1] 1
It is ill-mannered to attach an object and not tell us that was done.
So why is "3" as an index returning 1? because the internal
representation of a factor was used by the parser. Furthermore even
the usual dodge of wrapping as.character around f1 will not succeed
since f1 didn't record where it got the value of "3", and there is no
L1["3"] or L1[["3"]] only an L1[[3]] and an L1[3]
> L1[[as.character(f1)]]
NULL
So you need the "full-court [factor] press":
> L1[[as.numeric(as.character(f1))]]
[1] 3
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