On Jan 4, 2012, at 12:21 PM, Rich Shepard wrote:
On Tue, 3 Jan 2012, David Winsemius wrote:
burns.tds[ !duplicated(burns.tds) , ]
Apparently it does not matter if the site column in the data frame
is a
factor or a character, read.zoo() generates the same error. Applying
the
above produces a long list starting with:
burns.tds[!duplicated(burns.tds), ]
site sampdate quant
599 BC-3 1992-03-27 0.100
600 BC-3 1992-04-30 0.100
601 BC-3 1992-05-30 0.100
603 BC-3 1992-06-19 0.100
1214 BC-3 1992-07-20 0.100
1215 BC-3 1992-08-10 0.100
1216 BC-3 1992-09-30 0.100
1217 BC-3 1992-10-29 0.100
1218 BC-3 1992-11-19 0.100
1929 BC-3 1995-03-23 8.080
I don't know how to interpret this. I don't see two rows with the
same
values, but ~ 500 rows each with a different value. What is
duplicated? The
entire row? The site ID?
You didn't ask for what was duplicated, but rather what was NOT
duplicated with that code. In the case of a dataframe it is the entire
row that is tested.
?duplicated has some examples, but those do not show the output of
the
function nor explain what's duplicated.
I need to get past this blockage and appreciate your help in
determining
why read.zoo() sees duplicates when the database table has none, and
how to
resolve this issue.
I think you need to reduce this problem to a dataframe that you either
post an access method for or use dput() to include. Then you need to
say what you goals are and what code is not working on that example.
TIA,
Rich
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David Winsemius, MD
West Hartford, CT
______________________________________________
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
