Dear R-ers,
I feel I am close, but can't get it quite right.
Thanks a lot for your help!
Dimitri
# I have 2 data frames:
x<-data.frame(a=c("aa","aa","ab","ab","ba","ba","bb","bb"),b=c(1:2,1:2,1:2,1:2),d=c(10,20,30,40,50,60,70,80))
y<-data.frame(a2=c("aa","aa","ba","ba"),a3=c("ab","ab","bb","bb"),b=c(1:2,1:2),e1=c(100,200,300,400),e2=c(101,201,301,401))
(x);(y)
# I'd like to merge them so that the result looks like this:
desired<-data.frame(a=c("aa","aa","ab","ab","ba","ba","bb","bb"),b=c(1:2,1:2,1:2,1:2),d=c(10,20,30,40,50,60,70,80),
e1=c(100,200,100,200,300,400,300,400),e2=c(101,201,101,201,301,401,301,401))
(desired)
# In other words, I want column e1 and e2 entries from data frame y to
be repeated based on matching of column a from x and columns a2 and
then a3 from y.
# I am trying step-by-step - first I am using column a2 from data
frame y for merging:
out1<-merge(x,y[-2],by.x=c("a","b"),by.y=c("a2","b"),all.x=T,all.y=F)
(out1) # looking good - half of the job is done
# Step2 - does not work
# next line produces columns e1 and e2 twice (in real life I have tons
of columns like e1 and e2):
merge(out1,y[-1],by.x=c("a","b"),by.y=c("a3","b"),all.x=T,all.y=F)
# next line also doesn't do the job:
merge(out1,y[-1],by.x=c("a","b","e1","e2"),by.y=c("a3","b","e1","e2"),all.x=T,all.y=F)
# Finally, I tried this approach:
out1<-merge(x,y[-2],by.x=c("a","b"),by.y=c("a2","b"),all.x=T,all.y=F)
out2<-merge(x,y[-1],by.x=c("a","b"),by.y=c("a3","b"),all.x=T,all.y=F)
(out1); (out2)
# Now I need to merge these 2 - however, the next line doubles the
number of entries:
merge(out1,out2,by=names(out1),all.x=T,all.y=T)
--
Dimitri Liakhovitski
marketfusionanalytics.com
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