Comments in line

On 24/12/2014 22:09, Ruzan Udumyan wrote:
Dear Michael,

Thank you very much for your reply. The more complete information is as
follows:

I want to do a mediation analysis following the below-mentioned syntax
from:
http://www.biomedcentral.com/content/supplementary/1471-2288-14-9-s1.pdf

I did not define categorical variables as logical variables. I modelled
them as /*factor.X, factor.Xstar*/, etc. the X variable has 3 levels.

It is all sorted but I am not sure about the last bit: to return the
values. For example, I could not figure out what unname stands for, and
whether it is correct to use when variables are modelled as factor.X.

I wrote the syntax as:

  TE2 = exp(sum(coef(cox)[c('factor(X)2', 'factor(Xstar)2')]))   # level
2 vs level 1(ref)
  TE3 = exp(sum(coef(cox)[c('factor(X)3', 'factor(Xstar)3')]))   # level
3 vs level 1(ref)

   DE2 = exp(unname(coef(cox)['factor(X)2']))
   DE3 = exp(unname(coef(cox)['factor(X)3']))

   IE2 = exp(sum(coef(cox)['factor(Xstar)2']))
   IE3 = exp(sum(coef(cox)['factor(Xstar)3']))
   PM2 = log(IE2) / log(TE2)
   PM3 = log(IE3) / log(TE3)


Thank you very much for your help.

Wishing you happy holidays,
Ruzan


*The script from the link:*
doEffectDecomp = function(d)
{
  # Step 1: Replicate exposure variable, predict mediator
  d$TrialTemp = d$Trial
  MOpti = glm(Opti ~ TrialTemp + Age5 + ECOG + Ascit + Comorb + Histo +
  Grade, family=binomial(), data=d)
# Step 2: Replicate data with different exposures for the mediator
  d1 = d2 = d
  d1$Med = d1$Trial
  d2$Med = !d2$Trial
  newd = rbind(d1, d2)
# Step 3: Compute weights for the mediator
  newd$TrialTemp = newd$Trial
  w = predict(MOpti, newdata=newd, type='response')
  direct = ifelse(newd$Opti, w, 1-w)
  newd$TrialTemp = newd$Med
  w = predict(MOpti, newdata=newd, type='response')
  indirect = ifelse(newd$Opti, w, 1-w)
  newd$W = indirect/direct
# Step 4: Weighted Cox Model
  cox = coxph(Surv(OS, Status) ~ Trial + Med + Age5 + ECOG + Ascit +
  Comorb + Histo + Grade, weight=W, data=newd)
# Return value: Estimates for total, direct, indirect effect
  TE = exp(sum(coef(cox)[c('TrialTRUE', 'MedTRUE')]))
  DE = exp(unname(coef(cox)['TrialTRUE']))
  IE = exp(sum(coef(cox)['MedTRUE']))
  PM = log(IE) / log(TE)
  return(c(exp(coef(cox)), TE=TE, DE=DE, IE=IE, PM=PM))
}

On Tue, Dec 23, 2014 at 6:21 PM, Michael Dewey <i...@aghmed.fsnet.co.uk
<mailto:i...@aghmed.fsnet.co.uk>> wrote:

    Inline comments

    On 23/12/2014 09:42, Ruzan Udumyan wrote:

        Dear All,

        I am not familiar with R language well. Could you please help me
        interpret
        these commands?:


           TE = exp(sum(coef(cox)[c('aTRUE', 'bTRUE')]))   - does it
        mean exp(coef(a
        variable) + coef(b variable)) ?


    You have not given us much to go on here.
    I assume if you go
    coef(cox)
    you will find elements labelled aTRUE and bTRUE which implies the
    existence of a logical covariate with values TRUE and FALSE.

You now tell me my assumption was wrong. Presumably you know what you are trying to do but we do not and you are not really helping us by giving us a load of code to read through with any details of the dataset.

 The
    author of the code is trying to do what you suggest.

           DE = exp(unname(coef(cox)['aTRUE'])__)  - what is unname for ?


    ?unname

        Thank you very much beforehand for your help.

        Wishing you happy holidays,
        Ruzan

                 [[alternative HTML version deleted]]
         > PLEASE do read the posting guide
        http://www.R-project.org/__posting-guide.html
        <http://www.R-project.org/posting-guide.html>
        and provide commented, minimal, self-contained, reproducible code.


    If you post again please do read the message above.


Commented, minimal, self-contained, reproducible code was asked for.



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    --
    Michael
    http://www.dewey.myzen.co.uk


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http://www.dewey.myzen.co.uk

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