Dear Maryam
Please keep the list cc'ed in as others will have better answers than me.
If dam has 700 members then sample (dam) gives you a random permutation
of dams, each once.
I did not understand the second part as i do not think you can have 30
sires each occurring 20 times. Did you mean 35 sires? You can follow the
same procedure as I suggested to do that.
I think you perhaps need to re-read some introductory material as you
are struggling over some fairly basic concepts here.
Michael.
On 12/01/2016 16:54, MARYAM wrote:
Dear Michael,
thanks a lot for your answering. I have question if i have 700 dam and 30 sire.
how can i write my ped thad dam use only once and sire use 20 time or 1:20 dam
with sire 1 then 21:40 dam with sire 2 and …
On Dey 22, 1394 AP, at 19:52, Michael Dewey <li...@dewey.myzen.co.uk> wrote:
Dear Maryam
sample(dam) would give you a random permutation of dams
sample(c(sire, sire)) would give you a random permutation of sires, each twice.
Does that help?
On 12/01/2016 05:53, maryam firoozi via R-help wrote:
Dear mr/madam
I want to mak a matrix with 10 row and 3 column . this matrix is pedigree. my
input
sire<- c(1,2,3,4,5)
count<- 0
sire<- cbind(sire,count)
dam<- c(1,2,3,4,5,6,7,8,9,10)
ped<-mstrix(NA,nrow=10,ncol=3)
for(i in 1:10){
Sire<- sample(sire[,1],1)
a<- which(sire[,1]==Sire)
if(a){sire[a,2]<-sire[a,2]+1}
Dam<- sample(dam,1)
ped[i,1]<- 1:10
ped[i,2]<- Sire
ped[i,3]<- Dam}
i cant write a code that each sire use only twic not more in ped and Dam use
only once.
can you help me?
sincerely
firoozi
Sent from my iPhone
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--
Michael
http://www.dewey.myzen.co.uk/home.html
--
Michael
http://www.dewey.myzen.co.uk/home.html
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