Hello,
I try to calculate the mean of an array with a condition. My array is
B=c(181,101,420) in dimensions. And I want to find a specific member
in 3rd dimension (time monthly) based on a condition of another data
frame, A =c(420). My final array would be C=c(181,101,12) which 12 is
a monthly mean based on the condition of A.
what I tried is below but doesn't work.
#find the index with a condition larger than 0.5
index<-which(A>=0.5)
#convert the index to monthly
index1<-index%%12
#change 0 to 12 (Jan=1, Feb=2, and so on..)
index1[index1==0]<-12
for (i in 1:12){
dummy<-index[which(index1==i)]
C[,,i]<-apply(B[,,dummy],c(1,2), mean,na.rm=T)
}
The problem is when there is a month that doesnt meet the condition,
it will return 0 element.
apply(B[,,1],c(1,2), mean,na.rm=T) also produce an error.
Any solution and turnaround would be appreciated.
Thank you
Ani Jaya
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
