Try: format(d, "%a") or format(d, "%A") or as.POSIXlt(d)$wday
There is also day.of.week in chron. On Sat, Jul 11, 2009 at 3:42 PM, Mark Knecht <markkne...@gmail.com> wrote: > On Sat, Jul 11, 2009 at 12:05 PM, Gabor > Grothendieck<ggrothendi...@gmail.com> wrote: > > You want %Y, not %y. > > > > You might also want to look at the zoo package: > > > > library(zoo) > > z <- read.zoo("Date1.txt", header = TRUE, sep = ",", format = "%m/%d/%Y") > > > > or using chron: > > > > library(zoo) > > library(chron) > > z <- read.zoo("Date1.txt", header = TRUE, sep = ",", FUN = as.chron) > > > > There are three vignettes that come with zoo that have more info. > > > > Thanks Gabor. That solved the immediate problem. I appreciate the help. > > I'll take a look at zoo and chron. Any guidance on which package I > should look at for getting what day of the week a certain date is? > That's something I know I'll need. > > Cheers, > Mark > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.