Hi aegea,

Here is one:

m <- structure(c(6, 5, 20, 7, 8, 25, 14, 8, 9, 10, 11, 12, 13, 14,
1, 2, 3, 4, 5, 6, 7), .Dim = c(7L, 3L))

m1 <- m[m[,1] >= m[,2], ]
m1

m2 <- m[m[,1] < m[,2], ]
m2

Best,
Jorge


On Thu, Dec 3, 2009 at 10:12 PM, aegea <> wrote:

>
> Hello,
>
> I am working on seperate the matrix to two matrices but got trouble on
> doing
> it. Please give me some suggestions on doing this. Thanks a
> looooooooooooot!
>
> My original matrix m is as follows for example,
>
>     [,1] [,2] [,3]
> [1,]    6    8    1
> [2,]    5    9    2
> [3,]    20  10    3
> [4,]    7   11    4
> [5,]    8   12    5
> [6,]    25   13    6
> [7,]   14   14    7
>
> I want to generate two matrix m1 and m2
> if m[i, 1] <m[i,2], then the row is stored in new matrix m1, (i =1, ..., 7)
> if m[i,1]>=m[i,2], then the row is stored in new matrix m2.
>
> m1 supposed to be like:
>     [,1] [,2] [,3]
> [1,]    6    8    1
> [2,]    5    9    2
> [3,]    7   11    4
> [4,]    8   12    5
>
> m2 supposed to be like:
>     [,1] [,2] [,3]
> [1,]    20  10    3
> [2,]    25   13    6
> [3,]   14   14    7
>
>
> How can I code the if statement? Thank you very much
>
> --
> View this message in context:
> http://n4.nabble.com/how-to-seperate-a-matrix-tp948225p948225.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
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> and provide commented, minimal, self-contained, reproducible code.
>

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