Yes, because 1 / 2 is mathematically infinite in base 3, just like how
A=1/3 and B=10 doesn't terminate.
On 12/02/2024 07:31, Georgi Guninski wrote:
On Sat, Feb 10, 2024 at 6:24 PM Georgi Guninski<ggunin...@gmail.com> wrote:
```
def base_B_digits(A, B,prot=False):
digits=[]
fractional_part = A - int(A)
while fractional_part != 0:
digit = int(fractional_part * B)
digits.append(digit)
fractional_part = fractional_part * B - digit
if prot: print(fractional_part)
return digits
```
I am not sure the program must terminate.
Just for the record, this this digit extraction algorithm doesn't terminate
for A=0.5 and B=3 in sage and pari/gp.
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