Is the printed order important? If not, you can change the doctest to
something else that is actually testing something relevant, maybe like
sage: 'B' in frozenset(....)
True
or
sage: (define the frozenset S somehow)
sage: S == frozenset(['A', 'B', 'C'])
True
Or if necessary, mark the test as "# random".
On Tuesday, April 16, 2019 at 7:43:46 AM UTC-7, Daniel Krenn wrote:
>
> In Python2-SageMath we have
>
> sage: frozenset([frozenset(['A', 'B']), frozenset(['B', 'C'])])
> frozenset({frozenset({'B', 'C'}), frozenset({'A', 'B'})})
>
> in all my trials, whereas in Python3 we get all possible permutations of
> the elements at random.
>
> Even using
>
> sage: from IPython.lib.pretty import pretty
> sage: pretty(frozenset([frozenset(['A', 'B']), frozenset(['B', 'C'])]))
>
> displays the set of sets with random order. How to deal with this?
>
> Background: This comes from a doctest in
> sage.combinat.finite_state_machine, where this is a label of a state
> after some minimization etc.
>
> Best, Daniel
>
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