correction

scanimage --batch=preview.jpg --batch-count=1 --format=jpeg -d <scan
device> -x <max x> -y <max y> -l 0 -t 0 <special options user has selected>

On Thu, Jan 4, 2018 at 11:46 AM, Jeff Sadowski <jeff.sadow...@gmail.com> wrote:
> Because I will use the default resolution I will leave out that
> argument and I though about if the default scan area for -l and -t
> might not always be 0 so maybe I should do this
>
> scanimage --batch=preview.jpg --batch-count=1 --format=jpeg -d <scan
> device> --test-picture=Grid -x <max x> -y <max y> -l 0 -t 0
>
> On Thu, Jan 4, 2018 at 11:36 AM, Jeff <jf...@posteo.net> wrote:
>> On 04/01/18 19:14, Jeff Sadowski wrote:
>>> I'm thinking my best bet is to use the default resolution with max x and 
>>> max y.
>>
>> Exactly. A resolution of 1 is too small. This works fine for me:
>>
>> scanimage --batch=preview.jpg --batch-count=1 --format=jpeg -d test:1
>> --resolution=50 --test-picture=Grid -x 200 -y 200
>>
>> Regards
>>
>> Jeff
>>
>>
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