[lace-chat] maths question from a non mathematician

[scotlace]

This has nothing to do with lace but I've seen this question answered before - 
when I didn't need the info.  I have a magazine with patterns printed at 50% 
and 75% of full size.  What size do I need to set a photocopier to get 100% of 
pattern size?

Thank you.

Patricia in Wales

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Re: [lace] Dentelle Bigouden

[Maureen]

Thank you.  Yes the link works.  An interesting article,

Maureen
E Yorks
UK

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[lace] Dentelle Bigouden

[ann.humphreys]

Looking back through my National Geographic magazines I found an article about
the headdresses of Bigouden. I've copied this link. Hope it works.
http://ngm.nationalgeographic.com/2014/04/breton-women/fiegl-text
Ann
Yorkshire
UK

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Re: [lace-chat] maths question from a non mathematician

[lynrbailey]

The 50% has to be doubled (200%)  The 75% has to be at 133% (I think)  There 
should be a formula for it, but I don't know what it is.  

Clearly the 50% is half of what you want.  The 75% needs to be increased by 1/3 
of 75% in order for it to get to 100%  lrb

"My email sends out an automatic  message. Arachne members,
please ignore it. I read your emails."


-Original Message-
>From: scotl...@aol.com
>Sent: Oct 1, 2015 8:17 AM
>To: lace-chat@arachne.com
>Subject: [lace-chat] maths question from a non mathematician
>
>This has nothing to do with lace but I've seen this question answered before - 
>when I didn't need the info.  I have a magazine with patterns printed at 50% 
>and 75% of full size.  What size do I need to set a photocopier to get 100% of 
>pattern size?
>
>Thank you.
>
>Patricia in Wales
>
>To unsubscribe send email to majord...@arachne.com containing the line:
>unsubscribe lace-chat y...@address.here. For help, write to
>arachne.modera...@gmail.com. Photo site:
>http://www.flickr.com/photos/lacemaker/sets/

To unsubscribe send email to majord...@arachne.com containing the line:
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[lace] Every week an edging or an insertion

[Gon Homburg]

Dear Arachnes,

Yesterday the edging of this week was published on my site. I ran out of time 
to announce it to you right away. It is a Torchon edging with fans and a 
triangular ground.
Have fun making it.

Gon Homburg from a sunny Amsterdam, the Netherland. We will have tea in the 
garden.
gon.homb...@planet.nl

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Re: [lace-chat] maths question from a non mathematician

[scotlace]

 Thank you Lynne

That makes sense to me.  An answer many years ago used a formula which I didn't 
understand.  I'm going to save your answer for future reference.

Patricia

 


The 50% has to be doubled (200%)  The 75% has to be at 133% (I think)  There
should be a formula for it, but I don't know what it is.  

Clearly the 50% is
half of what you want.  The 75% needs to be increased by 1/3 of 75% in order for
it to get to 100%  lrb

To unsubscribe send email to majord...@arachne.com containing the line:
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arachne.modera...@gmail.com. Photo site:
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Re: [lace-chat] maths question from a non mathematician

[Brenda Paternoster]

I don’t think that formula is right.

If you want to double the area (A5 -> A4) you have to use 141% on a
photocopier.
That’s because you increase the length by 141% and the length by 141%
1.41 x 1.41 = 2

1.41 is the square root of 2

Going on that, if you want to increase the area by one third, the final area
will be 1.33
so square root of 1.33 = 1.54 so you set the photocopier to 154%

If you set the photocopier to 200% you double the length and double the width
which increase the area four times

Brenda

> On 1 Oct 2015, at 17:36, scotl...@aol.com wrote:
>
> Thank you Lynne
>
> That makes sense to me.  An answer many years ago used a formula which I
didn't understand.  I'm going to save your answer for future reference.
>
> Patricia
>
>
>
>
> The 50% has to be doubled (200%)  The 75% has to be at 133% (I think)
There
> should be a formula for it, but I don't know what it is.
>
> Clearly the 50% is
> half of what you want.  The 75% needs to be increased by 1/3 of 75% in order
for
> it to get to 100%  lrb
>
> To unsubscribe send email to majord...@arachne.com containing the line:
> unsubscribe lace-chat y...@address.here. For help, write to
> arachne.modera...@gmail.com. Photo site:
> http://www.flickr.com/photos/lacemaker/sets/

Brenda in Allhallows
paternos...@appleshack.com
www.brendapaternoster.co.uk

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Re: [lace] Dentelle Bigouden

[Liz and Ken Roberts]

Wow! Some of those would take a while just to put on!
Very beautiful! Thanks for the link.
Liz Roberts in beautiful, cool and sunny Missouri, USA


Looking back through my National Geographic magazines I found an article
about
the headdresses of Bigouden. I've copied this link. Hope it
works.
http://ngm.nationalgeographic.com/2014/04/breton-women/fiegl-text
Ann
Yorkshire
UK

-
To unsubscribe send email to majord...@arachne.com containing the line:
unsubscribe lace y...@address.here. For help, write to
arachne.modera...@gmail.com. Photo site:
http://www.flickr.com/photos/lacemaker/sets/

Re: [lace-chat] maths question from a non mathematician

[Joy Beeson]

I missed the original post:


Subject: [lace-chat] maths question from a non
mathematician

This has nothing to do with lace but I've seen this
question answered before - when I didn't need the info.
I have a magazine with patterns printed at 50% and 75%
of full size.  What size do I need to set a photocopier
to get 100% of pattern size?


It's ninth-grade algebra:  (If the word "algebra" gives you
brain-freeze, just read the part between dashed lines.)


Let P be the percent by which the pattern in the publication
has been enlarged or reduced.

Let C be the percent at which you need to set your copier.

Then P times C equals 100%:  PC = 1

Divide both sides of the equation by P:  C = 1/P
-
That is, you need to set the copier for the inverse of the
change that you want to undo.
-
You can punch "1 divide P equals" on your calculator, but if
the percentage happens to be a common fraction, you can just
turn it upside down.

50% is 1/2, so to undo it, you use 2, which is 200%.
(Remember that "per cent" means "divide by one hundred".)

75% is 3/4, so you would use 4/3, which is one and a third:
 133.33%

--
Joy Beeson
http://wlweather.net/PAGEJOY/
west of Fort Wayne, Indiana, U.S.A.

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Re: [lace-chat] maths question from a non mathematician

[scotlace]

 Thanks Joy,

The last part, which I would call arithmetic, I can understand.  I'm not going 
to say how long it is since I studied maths but suffice it to say that it is so 
long ago I've forgotten what it was about.  I managed O grade maths, (algebra, 
geometry, trigonometry) sat at 16, and that was my lot.  Without that, though, 
I wouldn't have got into university as all my other subjects were languages, 
history and literature.
Simple arithmetic I was always good at which is why I understand some of your 
explanation.  You are a good teacher!

Patricia


 

 






>> I have a
magazine with patterns printed at 50% and 75%
>> of full size.  What size do I
need to set a photocopier
>> to get 100% of pattern size?

It's ninth-grade
algebra:  (If the word "algebra" gives you
brain-freeze, just read the part
between dashed lines.)


Let P be the percent by which the pattern in the
publication
has been enlarged or reduced.

Let C be the percent at which you
need to set your copier.

Then P times C equals 100%:  PC = 1

Divide both
sides of the equation by P:  C =
1/P
-
That is, you
need to set the copier for the inverse of the
change that you want to
undo.
-
You can punch
"1 divide P equals" on your calculator, but if
the percentage happens to be a
common fraction, you can just
turn it upside down.

50% is 1/2, so to undo
it, you use 2, which is 200%.
(Remember that "per cent" means "divide by one
hundred".)

75% is 3/4, so you would use 4/3, which is one and a third:
 
133.33%

-- 
Joy Beeson
http://wlweather.net/PAGEJOY/
west of Fort Wayne,
Indiana, U.S.A.

To unsubscribe send email to majord...@arachne.com containing
the line:
unsubscribe lace-chat y...@address.here. For help, write
to
arachne.modera...@gmail.com. Photo
site:
http://www.flickr.com/photos/lacemaker/sets/

To unsubscribe send email to majord...@arachne.com containing the line:
unsubscribe lace-chat y...@address.here. For help, write to
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Re: [lace-chat] maths question from a non mathematician

[lynrbailey]

I knew there had to be an equation.  lrb


"My email sends out an automatic  message. Arachne members,
please ignore it. I read your emails."


-Original Message-
>From: Joy Beeson 
>Sent: Oct 1, 2015 4:29 PM
>To: lace-chat@arachne.com
>Subject: Re: [lace-chat] maths question from a non mathematician
>
>I missed the original post:
>
>>> Subject: [lace-chat] maths question from a non
>>> mathematician
>>> 
>>> This has nothing to do with lace but I've seen this
>>> question answered before - when I didn't need the info.
>>> I have a magazine with patterns printed at 50% and 75%
>>> of full size.  What size do I need to set a photocopier
>>> to get 100% of pattern size?
>
>It's ninth-grade algebra:  (If the word "algebra" gives you
>brain-freeze, just read the part between dashed lines.)
>
>
>Let P be the percent by which the pattern in the publication
>has been enlarged or reduced.
>
>Let C be the percent at which you need to set your copier.
>
>Then P times C equals 100%:  PC = 1
>
>Divide both sides of the equation by P:  C = 1/P
>-
>That is, you need to set the copier for the inverse of the
>change that you want to undo.
>-
>You can punch "1 divide P equals" on your calculator, but if
>the percentage happens to be a common fraction, you can just
>turn it upside down.
>
>50% is 1/2, so to undo it, you use 2, which is 200%.
>(Remember that "per cent" means "divide by one hundred".)
>
>75% is 3/4, so you would use 4/3, which is one and a third:
>  133.33%
>
>-- 
>Joy Beeson
>http://wlweather.net/PAGEJOY/
>west of Fort Wayne, Indiana, U.S.A.
>
>To unsubscribe send email to majord...@arachne.com containing the line:
>unsubscribe lace-chat y...@address.here. For help, write to
>arachne.modera...@gmail.com. Photo site:
>http://www.flickr.com/photos/lacemaker/sets/

To unsubscribe send email to majord...@arachne.com containing the line:
unsubscribe lace-chat y...@address.here. For help, write to
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