[PHP] asking about exe file
Can php execute .exe file ( compile from BorlandC) and view result on the browser ? PLease Help Me Rizal -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Newbie Question
Hi ,
Here's my problem :
I read a data file (no sql file) which contains 8 lines, and in each line, 8
datas
(ex: name1;picture1;title1;anything1;everything1;nothing1)
and when i run it I see only one picture(the second data) and not all of
them
If someone could help me
TYA
Here the code :
html
head
titleSolid/title
meta http-equiv=Content-Type content=text/html; charset=iso-8859-1
/head
body bgcolor=#FF text=#00
table width=384 border=1
?php
$row = 1;
$fp = fopen (album.dat,r);
while ($data = fgetcsv ($fp, 1000, ;))
{
$num = count ($data);
$row++;
if (isset($vignette))
{
print(tr);
print(td$vignette/td);
// I think it's wrong here but I dont know why
== print(tdimg src=\images/$photo\a href =
\prod.php?file=lecteur.dat\/a/td);
print(td$marque/td);
print(td$nom/td);
print(td$pdfproduit/td);
print(td$commprod/td);
print(/tr);
}
for ($c=0; $c$num; $c++)
switch ($c) {
case 0 :
{
$vignette = $data[$c];
break;
}
case 1 :
{
$photo= $data[$c];
break;
}
case 2 :
{
$marque= $data[$c];
break;
}
case 3 :
{
$nom = $data[$c];
break;
}
case 4 :
{
$pdfproduit= $data[$c];
break;
}
case 5 :
{
$commprod = $data[$c];
break;
}
}
}
?
/table
/body
/html
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Re: [PHP] Newbie Question
$fp = fopen($filename, 'r');
while ($l = fgets($fp, 1000))
{
list ($parts, $vignette, $marque, $nom, $pdfproduit, $commprod) =
explode (';', $l);
// now use the data
print p$parts/p; // or whatever
}
fclose ($fp);
On Mon, 8 Apr 2002, Hubert DAUL wrote:
Hi ,
Here's my problem :
I read a data file (no sql file) which contains 8 lines, and in each line, 8
datas
(ex: name1;picture1;title1;anything1;everything1;nothing1)
and when i run it I see only one picture(the second data) and not all of
them
If someone could help me
TYA
Here the code :
html
head
titleSolid/title
meta http-equiv=Content-Type content=text/html; charset=iso-8859-1
/head
body bgcolor=#FF text=#00
table width=384 border=1
?php
$row = 1;
$fp = fopen (album.dat,r);
while ($data = fgetcsv ($fp, 1000, ;))
{
$num = count ($data);
$row++;
if (isset($vignette))
{
print(tr);
print(td$vignette/td);
// I think it's wrong here but I dont know why
== print(tdimg src=\images/$photo\a href =
\prod.php?file=lecteur.dat\/a/td);
print(td$marque/td);
print(td$nom/td);
print(td$pdfproduit/td);
print(td$commprod/td);
print(/tr);
}
for ($c=0; $c$num; $c++)
switch ($c) {
case 0 :
{
$vignette = $data[$c];
break;
}
case 1 :
{
$photo= $data[$c];
break;
}
case 2 :
{
$marque= $data[$c];
break;
}
case 3 :
{
$nom = $data[$c];
break;
}
case 4 :
{
$pdfproduit= $data[$c];
break;
}
case 5 :
{
$commprod = $data[$c];
break;
}
}
}
?
/table
/body
/html
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[PHP] Copying Directory
Hello, I guess anyone have made the function to coppy directories, not files. I'd like to copy directory including sub directories to other place. Doesn't anyone has mades that kind of function?And please telll me. Thamks in advance. HiroshiAyukawa http://hoover.ktplan.ne.jp/kaihatsu/php_en/index.php?type=top -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Adding a in try.jpg!
I have a new very intriguing problem at hand. I have the name of my Images stored in my mySQL database in one column. Now when i pick the images, they are displayed as it as. However, they are the big images, and the thumbnails of those images are stored with an a at the end of thier names. That is, If the image is try.jpg , the thumbnail of the image is trya.jpg !! Now i want to display the thumbnail and not the large image. And unfortunately, my whole database contains the name of Large images and NOt the Thumbnails. How can i : 1. Insert a at the end of the name of the image, before the .extension through PHP. The problems are that the names are stored in the database WITH the extesion. And the extensions also vary, some are JPG and some are GIF. So in my datase i have images as try.jpg or something.gif! How can i insert an a at the end of the name before the . ? 2. OR.. can i insert the a before the . in the image name in my mySQL database itself. Either of the two solutions can work for me. Thanks, T. Edison Jr. __ Do You Yahoo!? Yahoo! Tax Center - online filing with TurboTax http://taxes.yahoo.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Adding a in try.jpg!
(untested)
$newname = eregi_replace('\.jpg$', 'a.jpg', $oldname);
No point messing up your database; just use something like the above when
you're outputting the image tags for the thumbnails.
miguel
On Mon, 8 Apr 2002, Thomas Edison Jr. wrote:
I have a new very intriguing problem at hand.
I have the name of my Images stored in my mySQL
database in one column. Now when i pick the images,
they are displayed as it as. However, they are the big
images, and the thumbnails of those images are stored
with an a at the end of thier names.
That is,
If the image is try.jpg , the thumbnail of the image
is trya.jpg !!
Now i want to display the thumbnail and not the large
image. And unfortunately, my whole database contains
the name of Large images and NOt the Thumbnails.
How can i :
1. Insert a at the end of the name of the image,
before the .extension through PHP.
The problems are that the names are stored in the
database WITH the extesion. And the extensions also
vary, some are JPG and some are GIF. So in my datase i
have images as try.jpg or something.gif! How can i
insert an a at the end of the name before the . ?
2. OR.. can i insert the a before the . in the
image name in my mySQL database itself.
Either of the two solutions can work for me.
Thanks,
T. Edison Jr.
__
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Re: [PHP] Adding a in try.jpg!
$parts = preg_split('/\./', $filename);
$new_filename = $parts[0] . a.jpg;
(Not tested, but _should_ work.)
/bsh/
Thomas Edison Jr. wrote:
I have a new very intriguing problem at hand.
I have the name of my Images stored in my mySQL
database in one column. Now when i pick the images,
they are displayed as it as. However, they are the big
images, and the thumbnails of those images are stored
with an a at the end of thier names.
That is,
If the image is try.jpg , the thumbnail of the image
is trya.jpg !!
Now i want to display the thumbnail and not the large
image. And unfortunately, my whole database contains
the name of Large images and NOt the Thumbnails.
How can i :
1. Insert a at the end of the name of the image,
before the .extension through PHP.
The problems are that the names are stored in the
database WITH the extesion. And the extensions also
vary, some are JPG and some are GIF. So in my datase i
have images as try.jpg or something.gif! How can i
insert an a at the end of the name before the . ?
2. OR.. can i insert the a before the . in the
image name in my mySQL database itself.
Either of the two solutions can work for me.
Thanks,
T. Edison Jr.
__
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Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
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| All opinions and technical advice offered in this message are my |
| own and not necessarily endorsed by my employer. |
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Re: [PHP] Adding a in try.jpg!
On Monday 08 April 2002 15:41, Thomas Edison Jr. wrote: How can i : 1. Insert a at the end of the name of the image, before the .extension through PHP. The problems are that the names are stored in the database WITH the extesion. And the extensions also vary, some are JPG and some are GIF. So in my datase i have images as try.jpg or something.gif! How can i insert an a at the end of the name before the . ? 2. OR.. can i insert the a before the . in the image name in my mySQL database itself. Loads of ways to do it. Here's one: explode() the file name on . then concatenate an a onto the second from last element, then implode(). -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* Don't worry. Life's too long. -- Vincent Sardi, Jr. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Copying Directory
#
#
# boolean copy_dirs ( string src_dir, string target_dir )
#
#
# copy shopdirectories into a new shop
#
# Function Parameters:
# string src_dir: source directory
# string target_dir: target directory
#
# Return Values:
# 0 - error while copying
# 1 - files copied successfully
#
function copy_dirs ( $src_dir, $target_dir ) {
$src_dir = ereg_replace ( /$, , $src_dir );
$target_dir = ereg_replace ( /$, , $target_dir );
if ( filetype ( $src_dir ) != dir ):
return (0);
endif;
if ( !file_exists ( $target_dir ) ):
mkdir ( $target_dir, 0777 );
endif;
$hdl = opendir ( $src_dir );
while ( ( $file = readdir ( $hdl ) ) !== false ):
if ( $file != . $file != .. $file != ):
if ( filetype ( $src_dir./.$file) == dir ):
if ( filetype ( $src_dir./.$file) == dir ):
if ( !copy_dirs ( $src_dir./.$file,
$target_dir./.$file ) ):
return (0);
endif;
else:
if ( !copy ( $src_dir./.$file, $target_dir./.$file ) ):
return (0);
endif;
endif;
endwhile;
return (1);
}
Hiroshi Ayukawa [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hello,
I guess anyone have made the function to coppy directories, not files.
I'd like to copy directory including sub directories to other place.
Doesn't anyone has mades that kind of function?And please telll me.
Thamks in advance.
HiroshiAyukawa
http://hoover.ktplan.ne.jp/kaihatsu/php_en/index.php?type=top
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[PHP] Re: Copying Directory
there was a typo...this one should work
#
#
# boolean copy_dirs ( string src_dir, string target_dir )
#
#
# copy a directory with subdirectories to a target directory
#
# Function Parameters:
# string src_dir: source directory
# string target_dir: target directory
#
# Return Values:
# 0 - error while copying
# 1 - files copied successfully
#
function copy_dirs ( $src_dir, $target_dir ) {
$src_dir = ereg_replace ( /$, , $src_dir );
$target_dir = ereg_replace ( /$, , $target_dir );
if ( filetype ( $src_dir ) != dir ):
return (0);
endif;
if ( !file_exists ( $target_dir ) ):
mkdir ( $target_dir, 0777 );
endif;
$hdl = opendir ( $src_dir );
while ( ( $file = readdir ( $hdl ) ) !== false ):
if ( $file != . $file != .. $file != ):
if ( filetype ( $src_dir./.$file) == dir ):
if ( !copy_dirs ( $src_dir./.$file,
$target_dir./.$file ) ):
return (0);
endif;
else:
if ( !copy ( $src_dir./.$file, $target_dir./.$file ) ):
return (0);
endif;
endif;
endwhile;
return (1);
}
Hiroshi Ayukawa [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hello,
I guess anyone have made the function to coppy directories, not files.
I'd like to copy directory including sub directories to other place.
Doesn't anyone has mades that kind of function?And please telll me.
Thamks in advance.
HiroshiAyukawa
http://hoover.ktplan.ne.jp/kaihatsu/php_en/index.php?type=top
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Re: [PHP] Adding a in try.jpg! Problems!
Hi,
Thanks for your relies. There are a couple of
problems. Firstly, i'm picking the filename from the
database, so my code is something like this :
if ($myrow = mysql_fetch_array($result)) {
do {
echo(
img src=\images\\$myrow[ilmage]\
);
} while ($myrow = mysql_fetch_array($result));
}
Now the filename is actually stored in $myrow[ilmage]
How do i perform the spliting adding functions on
$myrow[ilmage] ??
Secondly, all images are not .JPG, some are jpg
others are gif !!!
Thank you..
T. Edison Jr.
--- Miguel Cruz [EMAIL PROTECTED] wrote:
(untested)
$newname = eregi_replace('\.jpg$', 'a.jpg',
$oldname);
No point messing up your database; just use
something like the above when
you're outputting the image tags for the thumbnails.
miguel
On Mon, 8 Apr 2002, Thomas Edison Jr. wrote:
I have a new very intriguing problem at hand.
I have the name of my Images stored in my mySQL
database in one column. Now when i pick the
images,
they are displayed as it as. However, they are the
big
images, and the thumbnails of those images are
stored
with an a at the end of thier names.
That is,
If the image is try.jpg , the thumbnail of the
image
is trya.jpg !!
Now i want to display the thumbnail and not the
large
image. And unfortunately, my whole database
contains
the name of Large images and NOt the Thumbnails.
How can i :
1. Insert a at the end of the name of the image,
before the .extension through PHP.
The problems are that the names are stored in the
database WITH the extesion. And the extensions
also
vary, some are JPG and some are GIF. So in my
datase i
have images as try.jpg or something.gif! How
can i
insert an a at the end of the name before the
. ?
2. OR.. can i insert the a before the . in the
image name in my mySQL database itself.
Either of the two solutions can work for me.
Thanks,
T. Edison Jr.
__
Do You Yahoo!?
Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
=
Rahul S. Johari (Director)
**
Abraxas Technologies Inc.
Homepage : http://www.abraxastech.com
Email : [EMAIL PROTECTED]
Tel : 91-4546512/4522124
***
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[PHP] Re: PHP from HTML
THANKS! That works!! Except on PHP side I have to produce javascript code without script tag, like xTest.php - SERVER1 with PHP document.write(?php echo(\This WORKS!!!\); ?); on server 2 I just have to write this inside script tag, like HTML file on SERVER2 WITHOUT PHP html body script src=...server1.../test.php/script /body /html Thanks again! Have a nice day Matjaz Prtenjak One more compatible workaround would be to have your PHP return JavaScript: script lang=javascript1.1 document.write(Hello from Server1); /script In the HTML page on server2: script src=http://server1/xTest.php;/script Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Adding a in try.jpg! Problems!
$thumbnail = eregi_replace('\.jpg$', 'a.jpg', $myrow['ilmage']);
$thumbnail = eregi_replace('\.gif$', 'a.gif', $thumbnail);
It's no problem to do it twice in a row; it'll pick up one or the other.
miguel
On Mon, 8 Apr 2002, Thomas Edison Jr. wrote:
Hi,
Thanks for your relies. There are a couple of
problems. Firstly, i'm picking the filename from the
database, so my code is something like this :
if ($myrow = mysql_fetch_array($result)) {
do {
echo(
img src=\images\\$myrow[ilmage]\
);
} while ($myrow = mysql_fetch_array($result));
}
Now the filename is actually stored in $myrow[ilmage]
How do i perform the spliting adding functions on
$myrow[ilmage] ??
Secondly, all images are not .JPG, some are jpg
others are gif !!!
Thank you..
T. Edison Jr.
--- Miguel Cruz [EMAIL PROTECTED] wrote:
(untested)
$newname = eregi_replace('\.jpg$', 'a.jpg',
$oldname);
No point messing up your database; just use
something like the above when
you're outputting the image tags for the thumbnails.
miguel
On Mon, 8 Apr 2002, Thomas Edison Jr. wrote:
I have a new very intriguing problem at hand.
I have the name of my Images stored in my mySQL
database in one column. Now when i pick the
images,
they are displayed as it as. However, they are the
big
images, and the thumbnails of those images are
stored
with an a at the end of thier names.
That is,
If the image is try.jpg , the thumbnail of the
image
is trya.jpg !!
Now i want to display the thumbnail and not the
large
image. And unfortunately, my whole database
contains
the name of Large images and NOt the Thumbnails.
How can i :
1. Insert a at the end of the name of the image,
before the .extension through PHP.
The problems are that the names are stored in the
database WITH the extesion. And the extensions
also
vary, some are JPG and some are GIF. So in my
datase i
have images as try.jpg or something.gif! How
can i
insert an a at the end of the name before the
. ?
2. OR.. can i insert the a before the . in the
image name in my mySQL database itself.
Either of the two solutions can work for me.
Thanks,
T. Edison Jr.
__
Do You Yahoo!?
Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
=
Rahul S. Johari (Director)
**
Abraxas Technologies Inc.
Homepage : http://www.abraxastech.com
Email : [EMAIL PROTECTED]
Tel : 91-4546512/4522124
***
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Re: [PHP] Adding a in try.jpg! Problems!
Do the explode and implodes like that one fellow mentioned.
So basically:
while ($myrow = mysql_fetch_array($result)) {
$img = explode('.',$myrow[ilmage]);
echo img src=\images/{$img[0]}a$img[1]\br /
}
What this will do is take your image split the image at the '.' then echo it
with the 'a'.. Hope it helps!
Rick
Be kind. Everyone you meet is fighting a hard battle - John Watson
From: Thomas Edison Jr. [EMAIL PROTECTED]
Date: Mon, 8 Apr 2002 01:17:51 -0700 (PDT)
To: Miguel Cruz [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Adding a in try.jpg! Problems!
Hi,
Thanks for your relies. There are a couple of
problems. Firstly, i'm picking the filename from the
database, so my code is something like this :
if ($myrow = mysql_fetch_array($result)) {
do {
echo(
img src=\images\\$myrow[ilmage]\
);
} while ($myrow = mysql_fetch_array($result));
}
Now the filename is actually stored in $myrow[ilmage]
How do i perform the spliting adding functions on
$myrow[ilmage] ??
Secondly, all images are not .JPG, some are jpg
others are gif !!!
Thank you..
T. Edison Jr.
--- Miguel Cruz [EMAIL PROTECTED] wrote:
(untested)
$newname = eregi_replace('\.jpg$', 'a.jpg',
$oldname);
No point messing up your database; just use
something like the above when
you're outputting the image tags for the thumbnails.
miguel
On Mon, 8 Apr 2002, Thomas Edison Jr. wrote:
I have a new very intriguing problem at hand.
I have the name of my Images stored in my mySQL
database in one column. Now when i pick the
images,
they are displayed as it as. However, they are the
big
images, and the thumbnails of those images are
stored
with an a at the end of thier names.
That is,
If the image is try.jpg , the thumbnail of the
image
is trya.jpg !!
Now i want to display the thumbnail and not the
large
image. And unfortunately, my whole database
contains
the name of Large images and NOt the Thumbnails.
How can i :
1. Insert a at the end of the name of the image,
before the .extension through PHP.
The problems are that the names are stored in the
database WITH the extesion. And the extensions
also
vary, some are JPG and some are GIF. So in my
datase i
have images as try.jpg or something.gif! How
can i
insert an a at the end of the name before the
. ?
2. OR.. can i insert the a before the . in the
image name in my mySQL database itself.
Either of the two solutions can work for me.
Thanks,
T. Edison Jr.
__
Do You Yahoo!?
Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
=
Rahul S. Johari (Director)
**
Abraxas Technologies Inc.
Homepage : http://www.abraxastech.com
Email : [EMAIL PROTECTED]
Tel : 91-4546512/4522124
***
__
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Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
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Re: [PHP] Adding a in try.jpg! SOLVED!!
Hi,
Thanks.. actually that problem is solved, this is what
i used :
$myrow[ilmage] = eregi_replace('\.jpg$', 'a.jpg',
$myrow[ilmage]);
$myrow[ilmage] = eregi_replace('\.gif$', 'a.gif',
$myrow[ilmage]);
and it's now showing the small images with the a!!
Thanks AGAIN!
T. Edison Jr.
--- Miguel Cruz [EMAIL PROTECTED] wrote:
(untested)
$newname = eregi_replace('\.jpg$', 'a.jpg',
$oldname);
No point messing up your database; just use
something like the above when
you're outputting the image tags for the thumbnails.
miguel
On Mon, 8 Apr 2002, Thomas Edison Jr. wrote:
I have a new very intriguing problem at hand.
I have the name of my Images stored in my mySQL
database in one column. Now when i pick the
images,
they are displayed as it as. However, they are the
big
images, and the thumbnails of those images are
stored
with an a at the end of thier names.
That is,
If the image is try.jpg , the thumbnail of the
image
is trya.jpg !!
Now i want to display the thumbnail and not the
large
image. And unfortunately, my whole database
contains
the name of Large images and NOt the Thumbnails.
How can i :
1. Insert a at the end of the name of the image,
before the .extension through PHP.
The problems are that the names are stored in the
database WITH the extesion. And the extensions
also
vary, some are JPG and some are GIF. So in my
datase i
have images as try.jpg or something.gif! How
can i
insert an a at the end of the name before the
. ?
2. OR.. can i insert the a before the . in the
image name in my mySQL database itself.
Either of the two solutions can work for me.
Thanks,
T. Edison Jr.
__
Do You Yahoo!?
Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
=
Rahul S. Johari (Director)
**
Abraxas Technologies Inc.
Homepage : http://www.abraxastech.com
Email : [EMAIL PROTECTED]
Tel : 91-4546512/4522124
***
__
Do You Yahoo!?
Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
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[PHP] difficulty in solving the unknown warning
i am a php programmer whose learning expr. is about 2 months. whatever running script of php that written by other php programmer or me, i always see the warning below shown, why this occurs? how to avoid? Warning: Undefined variable: HTTP_VIA in g:\wwwroot\phpformmail\formmail.php on line 111 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Sendmail 8.10.2 headers
As you may know, headers included in the 4th argument of PHP's mail() are sent to the outgoing mail server. What header(s) can I send to sendmail 8.10.2 (running under Linux Redhat 6.2) in order for invalid e-mails be returned to my e-mail address rather than my hosting provider's default address? Thank you! Tony Rodriguez ([EMAIL PROTECTED]) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] sessions and passing variables
Is there a way to pass variables (objects) across the different sessions. I thought of sharing one object for all users that access my web site (it's an object that does some operations with files common to all users, like reading and writing). Any ideas? Tnx in advance. Armin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Copying Directory
Sorry, It didn't work.Mine too. ALL of the files inside the deeoer directory come to top of the directory. I'll go on trying . Thanks. By the way , your script looks like Python script , dont'you? Hiroshi AYukawa http://hoover.ktplan.ne.jp/kaihatsu/php_en/index.php?type=top -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Sendmail 8.10.2 headers
On Monday 08 April 2002 15:44, Anthony Rodriguez wrote: As you may know, headers included in the 4th argument of PHP's mail() are sent to the outgoing mail server. What header(s) can I send to sendmail 8.10.2 (running under Linux Redhat 6.2) in order for invalid e-mails be returned to my e-mail address rather than my hosting provider's default address? Return-Path: [EMAIL PROTECTED]\r\n; -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* Pound for pound, the amoeba is the most vicious animal on earth. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Copying Directory
On Monday 08 April 2002 17:04, Hiroshi Ayukawa wrote: Sorry, It didn't work.Mine too. ALL of the files inside the deeoer directory come to top of the directory. I'll go on trying . Thanks. By the way , your script looks like Python script , dont'you? Probably the easiest way is to some system functions. If you're on some *nix system use cp, if on windows use xcopy. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* Think sideways! -- Ed De Bono */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Emulating a browser, parse cookies with PHP
At 07.04.2002 16:22, you wrote: Hi, I'm trying to make a PHP script that would go in a website and log in. The website uses cookie to authenticate with its services. I made HTTP GET requests using fsockopen and parsed the results back into a variable. However I cannot find the cookie info(Set-cookie) in the returned content. Is there special commands I have to send with the GET request in order for the server to send back cookies? Or am I just doing this all wrong? Any help will be appreciated! Lokk at sourceforge.net, look for 'snoopy', that´s what makes everything you need Oliver -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Copying Directory
Thanks, But I can try it ,cause I like PHP and I want to write a code tahat runs anyware. Actually, we use both *nix windows. I will announce if I could madde it. Regards, Hiroshi http://hoover.ktplan.ne.jp/kaihatsu/php_en/index.php?type=top -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Workaround for no cron?
hi you should try this free service http://www.webcron.org it is really great (supports authentication, stores resulting file...) and free, the site is in french though ! Regards _ Hassan El Forkani http://WarmAfrica.com EveryOne's Africa _ 08/04/2002 04:15:01, Steve Werby [EMAIL PROTECTED] a écrit: Leif K-Brooks [EMAIL PROTECTED] wrote: I have to wait for my host to compile php as binary for cron to work with php, and a lot of things on my site depend on cron. It's not my favorite solution from a security standpoint, but you could call the PHP scripts from cron using wget or lynx. wget even supports HTTP authentication and I *think* lynx does as well so you can password protect the scripts using .htaccess. And I'm assuming you have cron access since if you don't, having your host install PHP as a CGI won't cure that. g Does anyone have some sort of code that I could put at the top of all my pages so when they get visited, it checks to see if a script has been executed yet this time petiod, and if not yet, it does? Better to teach a man to fish...? Either create a db entry or text file entry with the timestamp of the last run of the scheduled script and have your calling scripts check the timestamp to see if it's time to run. Or any type of workaround for not having cron? Thanks! You just need access to a machine (can even be a Windows desktop) which can launch a URL at a specified time or you just need someone who can do the same via a cron job on one of their boxes. Hope that helps. -- Steve Werby President, Befriend Internet Services LLC http://www.befriend.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Newbie Question
try this:
html
head
titleSolid/title
meta http-equiv=Content-Type content=text/html; charset=iso-8859-1
/head
body bgcolor=#FF text=#00
table width=384 border=1
?php
$fp = fopen (album.dat,r);
while ($data = fgetcsv ($fp, 1000, ;))
{
if (isset($data[0]))
{
print(tr);
print(td.$data[0]./td);
print(tdimg src=\images/.$data[1].\a href
=\prod.php?file=lecteur.dat\/a/td);
print(td.$data[2]./td);
print(td.$data[3]./td);
print(td.$data[4]./td);
print(td.$data[5]./td);
print(/tr);
}
}
?
/table
/body
/html
Hubert Daul [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hi ,
Here's my problem :
I read a data file (no sql file) which contains 8 lines, and in each line,
8
datas
(ex: name1;picture1;title1;anything1;everything1;nothing1)
and when i run it I see only one picture(the second data) and not all of
them
If someone could help me
TYA
Here the code :
html
head
titleSolid/title
meta http-equiv=Content-Type content=text/html; charset=iso-8859-1
/head
body bgcolor=#FF text=#00
table width=384 border=1
?php
$row = 1;
$fp = fopen (album.dat,r);
while ($data = fgetcsv ($fp, 1000, ;))
{
$num = count ($data);
$row++;
if (isset($vignette))
{
print(tr);
print(td$vignette/td);
// I think it's wrong here but I dont know why
== print(tdimg src=\images/$photo\a href =
\prod.php?file=lecteur.dat\/a/td);
print(td$marque/td);
print(td$nom/td);
print(td$pdfproduit/td);
print(td$commprod/td);
print(/tr);
}
for ($c=0; $c$num; $c++)
switch ($c) {
case 0 :
{
$vignette = $data[$c];
break;
}
case 1 :
{
$photo= $data[$c];
break;
}
case 2 :
{
$marque= $data[$c];
break;
}
case 3 :
{
$nom = $data[$c];
break;
}
case 4 :
{
$pdfproduit= $data[$c];
break;
}
case 5 :
{
$commprod = $data[$c];
break;
}
}
}
?
/table
/body
/html
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php-general Digest 8 Apr 2002 09:42:24 -0000 Issue 1274
php-general Digest 8 Apr 2002 09:42:24 - Issue 1274
Topics (messages 91954 through 92015):
Re: Test for one bit set?
91954 by: bvr
91955 by: Lars Torben Wilson
91956 by: Charlie Killian
Disabling bars on Browser
91957 by: David Johansen
91958 by: phplists.woodenpickle.com
91960 by: David Johansen
91962 by: phplists.woodenpickle.com
91973 by: Justin French
91976 by: Leif K-Brooks
91980 by: phplists.woodenpickle.com
91983 by: Justin French
91984 by: Justin French
91988 by: Jason Wong
Re: how to sort by value in associative array
91959 by: Chris Adams
Test for whole number.
91961 by: Charlie Killian
91963 by: Charlie Killian
91970 by: Tom Rogers
91971 by: Miguel Cruz
Function that escapes special caracters from regular expressions
91964 by: Leif K-Brooks
91965 by: Charlie Killian
91966 by: Matt Friedman
91968 by: CC Zona
Emulating a browser, parse cookies with PHP
91967 by: DRaGoNLz
92012 by: heinisch.creaction.de
Re: - REPOST - Flock manual clarification please ;-)
91969 by: Matt Friedman
91972 by: Jim Winstead
91982 by: Matt Friedman
xml-rpc for windows?
91974 by: dietrich
91977 by: Tyler Longren
91981 by: dietrich
Workaround for no cron?
91975 by: Leif K-Brooks
91986 by: Steve Werby
92014 by: gaouzief
asking about .exe file
91978 by: wong
91979 by: Martin Towell
Re: Phone number validation
91985 by: Timothy J. Luoma
Re: PHP from HTML
91987 by: Matja¾ Prtenjak
91989 by: Chris Adams
92002 by: Matja¾ Prtenjak
mod_php4
91990 by: javier
asking about exe file
91991 by: wong
Newbie Question
91992 by: Hubert DAUL
91993 by: Miguel Cruz
92015 by: Michael Virnstein
Copying Directory
91994 by: Hiroshi Ayukawa
91999 by: Michael Virnstein
92000 by: Michael Virnstein
92009 by: Hiroshi Ayukawa
92011 by: Jason Wong
92013 by: Hiroshi Ayukawa
Adding a in try.jpg!
91995 by: Thomas Edison Jr.
91996 by: Miguel Cruz
91997 by: Billy S Halsey
91998 by: Jason Wong
Re: Adding a in try.jpg! Problems!
92001 by: Thomas Edison Jr.
92003 by: Miguel Cruz
92004 by: Richard Baskett
Re: Adding a in try.jpg! SOLVED!!
92005 by: Thomas Edison Jr.
difficulty in solving the unknown warning
92006 by: erich
Sendmail 8.10.2 headers
92007 by: Anthony Rodriguez
92010 by: Jason Wong
sessions and passing variables
92008 by: rarmin
Administrivia:
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--
---BeginMessage---
This shows all integers from 1 to 10 that have the 2 least significant
bits set:
?php
for ($i = 1; $i = 10; $i++)
{
if ($i 3)
{
echo($i . \n);
}
}
?
bvr.
Charlie Killian wrote:
How can I test if a number only has on bit set?
So testing different numbers will return TRUE or FALSE:
testing 0001 would return TRUE.
testing 0011 would return FALSE.
TIA
Charlie
---End Message---
---BeginMessage---
On Sun, 2002-04-07 at 13:38, Charlie Killian wrote:
How can I test if a number only has on bit set?
So testing different numbers will return TRUE or FALSE:
testing 0001 would return TRUE.
testing 0011 would return FALSE.
TIA
Charlie
AND them bitwise:
?php
error_reporting(E_ALL);
$bit = 16;
$foo = bindec('0001');
$bar = bindec('0011');
echo $foo; $bar\n;
if ($foo $bit)
{
echo Bit 5 is set.\n;
}
else
{
echo Bit 5 is not set.\n;
}
if ($bar $bit)
{
echo Bit 5 is set.\n;
}
else
{
echo Bit 5 is not set.\n;
}
?
Torben
--
Torben Wilson [EMAIL PROTECTED]
http://www.thebuttlesschaps.com
http://www.hybrid17.com
http://www.inflatableeye.com
+1.604.709.0506
---End Message---
---BeginMessage---
Thanks to all those that replied. Especially Torben. (What have you been up
to?)
Miguel's solution works great.
Check out the example below:
?php
function isOneBitSet($n)
{
$x = log($n)/log(2);
return ($x == intval($x));
}
for ($i = 0; $i 32769; ++$i) {
if(isOneBitSet($i)) {
print($i, );
}
}
?
Prints out:
1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768,
Just what I wanted.
Thanks again,
Charlie
How can I test if a number only has on bit set?
So testing different numbers will return TRUE or FALSE:
testing 0001 would return TRUE.
testing 0011 would return FALSE.
Think back to math class when you were 14!
function isOneBitSet($n)
[PHP] $php_self doesnt work in netscape like it should!
Hi guys! $php_self and $php_referrer doesnt work the same in IE and Netscape When opening a page with IE they return for example http://localhost/directroy/index.php but in Netscape Navigator - http://localhost/directory/ Why? And how to solve this problem? Thanks -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Expire Session Date Older than Me!
I'm having trouble with the Expire date - It's being set at sometime before I was born. Any idea on how to fix this? HTTP/1.1 200 OK Date: Mon, 08 Apr 2002 10:07:31 GMT Server: Apache/1.3.22 (Unix) PHP/4.1.2 X-Powered-By: PHP/4.1.2 Set-Cookie: sess=6fc0c08e2030124a8518aa5eeff034d3; path=/ Expires: Thu, 19 Nov 1981 08:52:00 GMT Cache-Control: private, max-age=10800, pre-check=10800 Last-Modified: Fri, 30 Nov 2001 04:33:06 GMT Connection: close Content-Type: text/html -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Question
How to convert or discover from IPadress country visitors on my web ? roman -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: some kind of library loader
Hi Eric (and others who might help),
Actually I haven't tried the custom error handler for function or
class definiton not found errors because I read in the manual that
the processing is continued after the statement where the error
raised. I also thought of a little hacking in php's source, but I
haven't got too much experience in c.
Your idea looks fine to me, but I have one question. How do you
determine in the precompiler that which functions or classes are
really needed?
On our system it highly depends on the actual run. The template
parser parses the template file, finds our special tags, and creates
the appropriate objects to get the data for the tags from them. These
tags and classes are nested in each other. Now while I'm writing this
I have a new idea. I don't know if it will suit your needs (nor mine
yet), just a quick thought.
Each template classes (which gives about 50% of the whole code) are
derived from one main template class (it does the hard work).
The main problem is that there are many object creations in all over
the code, and they depend on the actual class or template tag.
So I'm trying to find a common part of the code, where I can handle
the missing class definition errors, or just start over some part of
the processing when an error occurs.
a template example might help to understand it better:
table ...
xarticle
trtd ...
xtitleb{xtext}b/xtitle
/tr/td
/xarticle
/table
The tags starting with x are our template tags (x... and {x...}),
and each container tag (x./x..) has it's own handler class.
In xarticle's handler object xtitle's handler is created, which
will raise an error if there's no class definition yet.
If catching the class not found errors would work I could set a
class not found error signal in a global variable, load the needed
class in the error handler. After the error handler finished, I could
check if the error signal is set in the mentioned common code and if
it is I could roll back all the processing of xtitle and start it
over this time with the already included class definition.
I can relatively easily find this common code, because of the
ancestor main template class, what all other template classes extend.
Because of the many roll backs this most likely wouldn't be faster
than the original code was. To make things faster I could store some
kind of cache for all the template files with the previously needed
classes (I can get it with get_defined_classes()). This would work
because the needed classes are mainly depend on the template in our
system (especialy the template classes). Next time when a page is
requested with the same template, I could just read the cache and
include all the previously needed classes.
So the sollution in general: find a common code where you can roll
back to some point where the line that caused the error can be
executed again.
I know my example was a little complicated, but I hope you can
understand it. Let me know if something isn't clear.
But now I checked if I can catch the Cannot instantiate non-existent
class error, and unfortunatelly not :((
For the developers of php: Is it hard to make this feature to work? I
would really appreciate it, and would be very very happy :))
Thanks and greetings,
Arpi
I have had a similar idea. I also tried the custom error handler
aproach and it didn't work here either. I have set the project
aside that I was thinking about it for but I do have some ideas
that would help and may be able to contribute. I wasn't even able
to get php to call my custom error handler for function not found
errors. How did you do that? Was there anything useful in the
context argument? My guess is that to get this aproach to work
would require hacking the code to php itself but the hack wouldn't
be very major. However I do have an alternate plan that has been
waiting for me to get around to building it is a simple parser that
will read a php file and get the required functions and classes and
then pre build a library file for just that page. The parsing
shouldn't be that dificult as all function calls begin with 'func('
and for classes checking for 'new classname' or 'classname::' would
give me a list of all items that need to be checked for. Then
simply build (from the source) a list of all builtin php functions
and allow those and check for declarations of inline functions and
classes while parsing and remove those. That would leave a list of
functions and classes that are external. Then build a database of
classes and functions either as a real database or simple an index
of the files that contain each resource. I don't think it would be
too hard. The next step would be to make a publicly available
archive of functions and classes that fit into this index. Or to
build it into pear.
Please keep in touch with me on this issue. Feel free to email me
off list if you want.
Eric
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[PHP] Transfer Session Vars to different server
Hi, I have two servers with Apache PHP - carrying out different tasks. However, I have got a task that requires one application to use both servers. One of the units holds a bunch of session vars - which I would like to transfer to the other unit, when scripts on this second unit are called. What is the best way to do this? Clearly, I don't want to do this as a list of vars in the URL - some of the vars are sensitive. I would appreciate any comments. Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] SELECT + PARSE ERROR
Hy,
I try to do a SELECT but when I test my code I
Have a parse error.
If someone can explain to me why.
Code:
$db = mysql_connect(newsmanga_db);$req =
"SELECT * FROM dvds WHERE nomdvd='".$nom."".$i"' "; /// PARSE ERROR IN
THIS LINE$res=mysql_query($req, $db);while ($ligne = mysql_fetch_object
($res)) {print "font size='2'
color='#FF'p align='center'";print
"$ligne-resume/p/font/td/tr";}mysql_free_result
($res);
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[PHP] Re: Transfer Session Vars to different server
If you store your session vars in database, there will be no problem with retrieving sessions vars... You even can use native php4 functions for handling sessions, storing them in DB... Look in php manual for session_set_save_handler() function, or write your completely own code for db sessions. P.S. By the way, anyone knows, is there possible to get access to other sessions' session variables, I mean to the variables, which are stored during other sessions, for instance, in order to find out, how many user are currently browsing my site. If I stored my sesss vars in DB, there wouldn't be any problem with this, but I store them using default php4 functions (in tmp dir in files and so on)... Chris [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi, I have two servers with Apache PHP - carrying out different tasks. However, I have got a task that requires one application to use both servers. One of the units holds a bunch of session vars - which I would like to transfer to the other unit, when scripts on this second unit are called. What is the best way to do this? Clearly, I don't want to do this as a list of vars in the URL - some of the vars are sensitive. I would appreciate any comments. Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] SELECT + PARSE ERROR
At 02:23 PM 4/8/2002 +0200, you wrote: Hy, I try to do a SELECT but when I test my code I Have a parse error. If someone can explain to me why. Code: $db = mysql_connect(newsmanga_db); $req = SELECT * FROM dvds WHERE nomdvd='.$nom..$i' ; /// PARSE ERROR IN THIS LINE Your missing a '.' after the $i . -Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] SELECT + PARSE ERROR
Hi
the error appears because of the comas erroned syntaxis.
why don't u try something easire as that :
$varalacon = $nom..$i; (i don't know if there is a space or not...in
bold)
$req = SELECT * FROM dvds WHERE nomdvd='$varalacon' ;
Hope it helps
SR
Jérome Moisy a écrit :
Hy, I try to do a SELECT but when I test my code I Have a parse
error.If someone can explain to me why. Code: $db =
mysql_connect(newsmanga_db);
$req = SELECT * FROM dvds WHERE nomdvd='.$nom..$i' ; /// PARSE
ERROR IN THIS LINE
$res=mysql_query($req, $db);
while ($ligne = mysql_fetch_object ($res)) {
print font size='2' color='#FF'p align='center';
print $ligne-resume/p/font/td/tr;
}
mysql_free_result ($res);
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Re: [PHP] SELECT + PARSE ERROR
On Mon, 8 Apr 2002, [iso-8859-1] Jérome Moisy wrote:
Hy,
I try to do a SELECT but when I test my code I Have a parse error.
If someone can explain to me why.
Code:
$db = mysql_connect(newsmanga_db);
$req = SELECT * FROM dvds WHERE nomdvd='.$nom..$i' ; /// PARSE ERROR IN THIS
LINE
$res=mysql_query($req, $db);
while ($ligne = mysql_fetch_object ($res)) {
print font size='2' color='#FF'p align='center';
print $ligne-resume/p/font/td/tr;
}
mysql_free_result ($res);
First glance, put quotes around newsmanga_db.
$db = mysql_connect(newsmanga_db);
However, it doesn't look like you would establish a connection to the
database even if you fixed the syntax error. Have a look at the PHP
manual in order to see the correct usage of this function. The
username/password parameters are optional, but I have a feeling that
newsmanga_db is the name of your database, not the database server
(usually localhost). You also need to select the database that you intend
to query.
http://www.php.net/manual/en/function.mysql-connect.php
http://www.php.net/manual/en/function.mysql-select-db.php
Personally, I'd use this code (going on what you have supplied and what I
believe to be true):
//---
mysql_connect(localhost, username, password);
mysql_select_db(newsmanga_db);
$req = SELECT * FROM dvds WHERE nomdvd = ' . $nom . $i . ';
$res = mysql_query($req);
while ($ligne = mysql_fetch_object($res))
{
print trtd;
print font size=\2\ color=\#FF\p align=\center\;
print $ligne-resume . /p/font/td/tr;
}
mysql_free_result($res);
//---
Cheers,
Nick Winfield.
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[PHP] Problems with libgd.so under linux
Php works in general (phpinfo()). The gd-lib however will not work for some reason. I tried extension=libgd.so in php.ini without any result. Anyone familiar with this problem? /M Green -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Question
At 08.04.2002 13:00, you wrote: How to convert or discover from IPadress country visitors on my web ? roman You have to make a DNSLOOKUP If you have a linux box (server setup) you can use system(nslookup -timeout=3 -retry=1 .$value) where $value is the IP-Number. This gives you the real name of the server your client asked from. the you have to extract the national-code, and got your country, or org, mil, com HTH Oliver -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] SELECT + PARSE ERROR
At 08.04.2002 14:23, you wrote:
Hy,
I try to do a SELECT but when I test my code I Have a parse error.
If someone can explain to me why.
Code:
$db = mysql_connect(newsmanga_db);
$req = SELECT * FROM dvds WHERE nomdvd='.$nom..$i' ; /// PARSE
ERROR IN THIS LINE
Try this :
$req = SELECT * FROM dvds WHERE nomdvd='.$nom.$i.' ;
or if you want a space between $nom and $i, put it between the Quotes
$res=mysql_query($req, $db);
while ($ligne = mysql_fetch_object ($res)) {
print font size='2' color='#FF'p align='center';
print $ligne-resume/p/font/td/tr;
}
mysql_free_result ($res);
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Re: [PHP] SELECT + PARSE ERROR
Thanks at All -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Transfer Session Vars to different server
At 08.04.2002 13:12, you wrote: Hi, I have two servers with Apache PHP - carrying out different tasks. However, I have got a task that requires one application to use both servers. One of the units holds a bunch of session vars - which I would like to transfer to the other unit, when scripts on this second unit are called. What is the best way to do this? Clearly, I don't want to do this as a list of vars in the URL - some of the vars are sensitive. I would appreciate any comments. Chris I hope both machines are linux, unix the scp-command (secure copy) will be your friend. So you save your vars in a file, scp this file from server1 to server2 and read the file, if it appears and is the correct one, read it in your script on the server2. To learn more about scp, see man scp HTH Oliver -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Question
On Mon, 8 Apr 2002, Roman Duriancik wrote: How to convert or discover from IPadress country visitors on my web ? You need to use the 'whois' protocol. I am sure you can find sample code snippets around. First, look up the address at whois.arin.net. Then, if delegated to one of the regional registries (like RIPE or APNIC), look it up again there. While this is the most effective way, keep in mind that you still can't determine with 100% certainty what country an IP address is in. Multinational corporations, large ISPs with their own international backbones, etc., will in many cases give you false results. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: sessions and passing variables
sure. if all users should have access to this instance of your object, then you could store the serialized object in a file, everyone has access to and unserialize it if needed.But don't forget to include your object-surcecode before unserializing the object, or you'll lose your methods. If users should also have write access to the object, you also have to make sure, that only one user can access the file for writing at one time, or your data gets probably screwed. The easiest way would be storing the object not in a file but in a database, so you don't have to care about locking. But do you really need the same instance of the object? why not simply perform a $obj = new Class(); -- Code for Storing: ?php $strData = serialize($data); $fp = fopen(globalObjectData.inc, w); fwrite($fp, $strData); fclose($fp); ? Code for accessing: ?php // include object source before unserializing include myObjectSrc.php; $fp = fopen(globalObjectData.inc, w); $strData = fread($fp, filesize(globalObjectData.inc)); fclose($fp); // so we have our object back $obj = unserialize($strData); Rarmin [EMAIL PROTECTED] schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Is there a way to pass variables (objects) across the different sessions. I thought of sharing one object for all users that access my web site (it's an object that does some operations with files common to all users, like reading and writing). Any ideas? Tnx in advance. Armin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problems with libgd.so under linux
At 08.04.2002 14:56, you wrote: Php works in general (phpinfo()). The gd-lib however will not work for some reason. I tried extension=libgd.so in php.ini without any result. Anyone familiar with this problem? /M Green Too few arguments ;-) Did you already compiled GD ? Did you compile php with gd support? Oliver -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Adding a in try.jpg! Problems!
$myrow[ilmage] = eregi_replace((\.[^\.]+)$, a\\1, $myrow[ilmage]);
and if ilmage isn't a constant use $myrow[ilmage].
Thomas Edison Jr. [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hi,
Thanks for your relies. There are a couple of
problems. Firstly, i'm picking the filename from the
database, so my code is something like this :
if ($myrow = mysql_fetch_array($result)) {
do {
echo(
img src=\images\\$myrow[ilmage]\
);
} while ($myrow = mysql_fetch_array($result));
}
Now the filename is actually stored in $myrow[ilmage]
How do i perform the spliting adding functions on
$myrow[ilmage] ??
Secondly, all images are not .JPG, some are jpg
others are gif !!!
Thank you..
T. Edison Jr.
--- Miguel Cruz [EMAIL PROTECTED] wrote:
(untested)
$newname = eregi_replace('\.jpg$', 'a.jpg',
$oldname);
No point messing up your database; just use
something like the above when
you're outputting the image tags for the thumbnails.
miguel
On Mon, 8 Apr 2002, Thomas Edison Jr. wrote:
I have a new very intriguing problem at hand.
I have the name of my Images stored in my mySQL
database in one column. Now when i pick the
images,
they are displayed as it as. However, they are the
big
images, and the thumbnails of those images are
stored
with an a at the end of thier names.
That is,
If the image is try.jpg , the thumbnail of the
image
is trya.jpg !!
Now i want to display the thumbnail and not the
large
image. And unfortunately, my whole database
contains
the name of Large images and NOt the Thumbnails.
How can i :
1. Insert a at the end of the name of the image,
before the .extension through PHP.
The problems are that the names are stored in the
database WITH the extesion. And the extensions
also
vary, some are JPG and some are GIF. So in my
datase i
have images as try.jpg or something.gif! How
can i
insert an a at the end of the name before the
. ?
2. OR.. can i insert the a before the . in the
image name in my mySQL database itself.
Either of the two solutions can work for me.
Thanks,
T. Edison Jr.
__
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Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
=
Rahul S. Johari (Director)
**
Abraxas Technologies Inc.
Homepage : http://www.abraxastech.com
Email : [EMAIL PROTECTED]
Tel : 91-4546512/4522124
***
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Re: [PHP] MAC file upload
On Saturday, April 6, 2002, at 11:44 AM, Shane McBride wrote: Hello, I am able to upload and download Macintosh files but they seem to lose their MIME type or extensions. I'm not sure what it is. I'm not a Mac dude. When you download the file It loses the file association. It's for a company I do work for that uses a lot of .ai and .psd files. Any ideas on this? You're possibly losing the resource fork of the files you are uploading, because the server is not an HFS+ filesystem. To the best of my knowledge there is nothing you can do about this via PHP, but there are probably tricks (like AppleScript) that you could use as a workaround, such as encoding the files in some transport-friendly format before uploading and decoding them upon download. Erik Erik Price Web Developer Temp Media Lab, H.H. Brown [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Adding a in try.jpg! Problems!
but if
$myrow[ilmage] = hallo.hmm.gif; your code won't work.
so better:
while ($myrow = mysql_fetch_array($result)) {
$img = explode('.',$myrow[ilmage]);
$img[count($img) - 1] .= a;
echo img src=\images/.implode('.', $img).\br /;
}
Richard Baskett [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Do the explode and implodes like that one fellow mentioned.
So basically:
while ($myrow = mysql_fetch_array($result)) {
$img = explode('.',$myrow[ilmage]);
echo img src=\images/{$img[0]}a$img[1]\br /
}
What this will do is take your image split the image at the '.' then echo
it
with the 'a'.. Hope it helps!
Rick
Be kind. Everyone you meet is fighting a hard battle - John Watson
From: Thomas Edison Jr. [EMAIL PROTECTED]
Date: Mon, 8 Apr 2002 01:17:51 -0700 (PDT)
To: Miguel Cruz [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Adding a in try.jpg! Problems!
Hi,
Thanks for your relies. There are a couple of
problems. Firstly, i'm picking the filename from the
database, so my code is something like this :
if ($myrow = mysql_fetch_array($result)) {
do {
echo(
img src=\images\\$myrow[ilmage]\
);
} while ($myrow = mysql_fetch_array($result));
}
Now the filename is actually stored in $myrow[ilmage]
How do i perform the spliting adding functions on
$myrow[ilmage] ??
Secondly, all images are not .JPG, some are jpg
others are gif !!!
Thank you..
T. Edison Jr.
--- Miguel Cruz [EMAIL PROTECTED] wrote:
(untested)
$newname = eregi_replace('\.jpg$', 'a.jpg',
$oldname);
No point messing up your database; just use
something like the above when
you're outputting the image tags for the thumbnails.
miguel
On Mon, 8 Apr 2002, Thomas Edison Jr. wrote:
I have a new very intriguing problem at hand.
I have the name of my Images stored in my mySQL
database in one column. Now when i pick the
images,
they are displayed as it as. However, they are the
big
images, and the thumbnails of those images are
stored
with an a at the end of thier names.
That is,
If the image is try.jpg , the thumbnail of the
image
is trya.jpg !!
Now i want to display the thumbnail and not the
large
image. And unfortunately, my whole database
contains
the name of Large images and NOt the Thumbnails.
How can i :
1. Insert a at the end of the name of the image,
before the .extension through PHP.
The problems are that the names are stored in the
database WITH the extesion. And the extensions
also
vary, some are JPG and some are GIF. So in my
datase i
have images as try.jpg or something.gif! How
can i
insert an a at the end of the name before the
. ?
2. OR.. can i insert the a before the . in the
image name in my mySQL database itself.
Either of the two solutions can work for me.
Thanks,
T. Edison Jr.
__
Do You Yahoo!?
Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
=
Rahul S. Johari (Director)
**
Abraxas Technologies Inc.
Homepage : http://www.abraxastech.com
Email : [EMAIL PROTECTED]
Tel : 91-4546512/4522124
***
__
Do You Yahoo!?
Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
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Re: [PHP] Question
this class does just that: http://phpclasses.warmafrica.com/browse.html/package/514.html 08/04/2002 13:49:44, [EMAIL PROTECTED] a écrit: At 08.04.2002 13:00, you wrote: How to convert or discover from IPadress country visitors on my web ? roman You have to make a DNSLOOKUP If you have a linux box (server setup) you can use system(nslookup -timeout=3 -retry=1 .$value) where $value is the IP-Number. This gives you the real name of the server your client asked from. the you have to extract the national-code, and got your country, or org, mil, com HTH Oliver -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] what's the best way to do redirect within PHP
Dear All, Another simple question: What is the best way to do redirect after a php file did some processing? Any helps would be greatly appreciated! --Wo -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Adding a in try.jpg! Problems!
typo..this one's right :)
while ($myrow = mysql_fetch_array($result)) {
$img = explode('.',$myrow[ilmage]);
$img[count($img) - 2] .= a;
echo img src=\images/.implode('.', $img).\br /;
}
Michael Virnstein [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
but if
$myrow[ilmage] = hallo.hmm.gif; your code won't work.
so better:
while ($myrow = mysql_fetch_array($result)) {
$img = explode('.',$myrow[ilmage]);
$img[count($img) - 1] .= a;
echo img src=\images/.implode('.', $img).\br /;
}
Richard Baskett [EMAIL PROTECTED] schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Do the explode and implodes like that one fellow mentioned.
So basically:
while ($myrow = mysql_fetch_array($result)) {
$img = explode('.',$myrow[ilmage]);
echo img src=\images/{$img[0]}a$img[1]\br /
}
What this will do is take your image split the image at the '.' then
echo
it
with the 'a'.. Hope it helps!
Rick
Be kind. Everyone you meet is fighting a hard battle - John Watson
From: Thomas Edison Jr. [EMAIL PROTECTED]
Date: Mon, 8 Apr 2002 01:17:51 -0700 (PDT)
To: Miguel Cruz [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Adding a in try.jpg! Problems!
Hi,
Thanks for your relies. There are a couple of
problems. Firstly, i'm picking the filename from the
database, so my code is something like this :
if ($myrow = mysql_fetch_array($result)) {
do {
echo(
img src=\images\\$myrow[ilmage]\
);
} while ($myrow = mysql_fetch_array($result));
}
Now the filename is actually stored in $myrow[ilmage]
How do i perform the spliting adding functions on
$myrow[ilmage] ??
Secondly, all images are not .JPG, some are jpg
others are gif !!!
Thank you..
T. Edison Jr.
--- Miguel Cruz [EMAIL PROTECTED] wrote:
(untested)
$newname = eregi_replace('\.jpg$', 'a.jpg',
$oldname);
No point messing up your database; just use
something like the above when
you're outputting the image tags for the thumbnails.
miguel
On Mon, 8 Apr 2002, Thomas Edison Jr. wrote:
I have a new very intriguing problem at hand.
I have the name of my Images stored in my mySQL
database in one column. Now when i pick the
images,
they are displayed as it as. However, they are the
big
images, and the thumbnails of those images are
stored
with an a at the end of thier names.
That is,
If the image is try.jpg , the thumbnail of the
image
is trya.jpg !!
Now i want to display the thumbnail and not the
large
image. And unfortunately, my whole database
contains
the name of Large images and NOt the Thumbnails.
How can i :
1. Insert a at the end of the name of the image,
before the .extension through PHP.
The problems are that the names are stored in the
database WITH the extesion. And the extensions
also
vary, some are JPG and some are GIF. So in my
datase i
have images as try.jpg or something.gif! How
can i
insert an a at the end of the name before the
. ?
2. OR.. can i insert the a before the . in the
image name in my mySQL database itself.
Either of the two solutions can work for me.
Thanks,
T. Edison Jr.
__
Do You Yahoo!?
Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
=
Rahul S. Johari (Director)
**
Abraxas Technologies Inc.
Homepage : http://www.abraxastech.com
Email : [EMAIL PROTECTED]
Tel : 91-4546512/4522124
***
__
Do You Yahoo!?
Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/
--
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[PHP] php and html image tag...
Ok here is my problem, I have a piece of code that queries the database pulls the results of a table into an array, on another file the results of that array are used with a require function and then each variable is echoed to the screen where I need it, I have a piece of javascript to open a pop up window and the code is as such... a href='javascript:openPopWin(?php echo $ad01; ?, 420,545, , 0, 0)'onmouseover=window.status='This weeks full page ad';return true As you can see I have placed the results of the array within my a href= tag and it works fine.. however the second part img src=?php echo $ad01_t; ? width=200 height=100 vspace=0 hspace=0 border=0/a Will not pull the results of the array into the page, I don't know if this is a valid piece or not, any help would be great. Thanks in advance. Jas -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] what's the best way to do redirect within PHP
On Monday 08 April 2002 22:00, Wo Chang wrote: Dear All, Another simple question: What is the best way to do redirect after a php file did some processing? Any helps would be greatly appreciated! Use header() to set a location. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* A diplomatic husband said to his wife, How do you expect me to remember your birthday when you never look any older? */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] what's the best way to do redirect within PHP
This is really simple: header(Location: .php); /Patrick www.optip.com -Original Message- From: Wo Chang [mailto:[EMAIL PROTECTED]] Sent: 08 April 2002 15:00 To: [EMAIL PROTECTED] Subject: [PHP] what's the best way to do redirect within PHP Dear All, Another simple question: What is the best way to do redirect after a php file did some processing? Any helps would be greatly appreciated! --Wo -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] what's the best way to do redirect within PHP
Le lundi 8 avril 2002, à 04:00 PM, Wo Chang a écrit : What is the best way to do redirect after a php file did some processing? Function header() ??? R. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Directory check
Does anyone know how to check a directory exiasts? Thanks in advance, Hiroshi Ayukawa http://hoover.ktplan.ne.jp/kaihatsu/php_en/index.php?type=top -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Disabling bars on Browser
Bob/pickle, I disagree -- Justin French has contributed a large number of helpful posts to this list. Just the other day, he responded to my query for advice -- http://marc.theaimsgroup.com/?l=php- generalm=101779873317529w=2 It is foolish to look the gift horse of free coding advice in the mouth (something that many companies will be happy to charge you for). I'm guilty too of making offtopic posts, but when someone reminds me of this I try not to take it personally, even when it makes me feel like an idiot in this public forum. I try to remember that a friendly tone of voice doesn't carry very well via email. There's plenty of other groups which will answer JavaScript-related questions, but it is your responsibility to find them. Erik On Sunday, April 7, 2002, at 10:09 PM, [EMAIL PROTECTED] wrote: Wow, you really feel like your better than everyone here don't you.. You rarely even give an answer that isn't blatent criticism of what someone posted or their ability to find information. You really need to stop. Bob Justin French [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... This is the wrong group/list for this post. The disabling of bars, or any sort of browser feature/appearance is NOT PHP. PHP is a server side langauge. Commonly, you would use JavaScript for such stuff, so I recommend you check out the millions of JavaScript sites and newsgroups on the web. Erik Price Web Developer Temp Media Lab, H.H. Brown [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] site map function..
I'm trying to write some code that will look at a table of records, and output a 'tree' of those records, based on a parent/child relationship betweent their respective record id numbers. Anyone written anything like this they would be willing to share? I'm up against a deadline, and I'm having a brain cramp trying to get my brain around the recursive aspect of doing it. Thanks in advance, Kelly -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] MAC file upload
Le lundi 8 avril 2002, à 03:45 PM, Erik Price a écrit : When you download the file It loses the file association. It's for a company I do work for that uses a lot of .ai and .psd files. Hi ! Have you tried with : $filesize = filesize($your_file); header(Content-type: .$your_mime_type); fread($your_file, $filesize); exit(); R. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: php and html image tag...
Please post more code. Can't help any further in the moment. Jas [EMAIL PROTECTED] schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Ok here is my problem, I have a piece of code that queries the database pulls the results of a table into an array, on another file the results of that array are used with a require function and then each variable is echoed to the screen where I need it, I have a piece of javascript to open a pop up window and the code is as such... a href='javascript:openPopWin(?php echo $ad01; ?, 420,545, , 0, 0)'onmouseover=window.status='This weeks full page ad';return true As you can see I have placed the results of the array within my a href= tag and it works fine.. however the second part img src=?php echo $ad01_t; ? width=200 height=100 vspace=0 hspace=0 border=0/a Will not pull the results of the array into the page, I don't know if this is a valid piece or not, any help would be great. Thanks in advance. Jas -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] newbie configuration question
On Friday, April 5, 2002, at 10:12 PM, Eric Kilgore wrote: I'm a newbie to Linux and Apache, not so new to php itself. I'm using Red Hat 7.2. The RPM installs apache with php, etc. as part of the standard install but --without-mysql in the configuration. I've read quit a bit on how you are supposed to be able to update the configuration etc. ./configure --with-mysql=/usr/bin/mysql etc. The trouble is I have no clue as to what directory I'm suppose to be running this in. I'm tempted to install a newer version of PHP (Red Hat 7.2 comes with 4.0.6) as the documentation on installing from source code seems to be a bit clearer. Can I install over the top of the existing module or would I have to uninstall that package first? If you are still having trouble with this, I have a log of a PHP upgrade that will show you how I went about it. But you've probably solved your problem by now. Needless to say, the source install is highly configurable and not very difficult, I recommend it over the RPM in almost any situation. Erik Erik Price Web Developer Temp Media Lab, H.H. Brown [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Directory check
file_exists will perform a check if the file, no matter if it's a directory, a regular file or a symlink. if you want to know if it is a directory use is_dir($file) or refer to the php manualHiroshi Ayukawa [EMAIL PROTECTED] schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Does anyone know how to check a directory exiasts? Thanks in advance, Hiroshi Ayukawa http://hoover.ktplan.ne.jp/kaihatsu/php_en/index.php?type=top -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: sessions and passing variables
Michael Virnstein wrote: you also have to make sure, that only one user can access the file for writing at one time, or your data gets probably screwed. The easiest way would be storing the object not in a file but in a database, so you don't have to care about locking. Tnx for the help, and one more question. If I would serialize object and store it in a file, I would need some way to implement object waiting at the locked file untill it's unlocked (some kind of semaphore or monitor). I can lock the file with flock, but I don't know how to put object on hold while the file it's requesting is locked. As for the database, I don't use database (it's an assignment that needs to be done using XML, so all data is in XML files) and I don't see much sence in using db for storing only one serialized object. But do you really need the same instance of the object? why not simply perform a $obj = new Class(); If I figure out how to put on hold object while some other object performs it's operations on locked file, I wouldn't need to use the same instance. -- Code for Storing: ?php $strData = serialize($data); $fp = fopen(globalObjectData.inc, w); fwrite($fp, $strData); fclose($fp); ? Code for accessing: ?php // include object source before unserializing include myObjectSrc.php; $fp = fopen(globalObjectData.inc, w); $strData = fread($fp, filesize(globalObjectData.inc)); fclose($fp); // so we have our object back $obj = unserialize($strData); Does anyone know how to implement monitor or semaphore or waiting queue on file resource? I'm using PHP 4.1.2 and Apache 1.2.23 on Windows platform. Armin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: php and html image tag...
Nevermind I got it fixed... I forgot to include a couple of fields from my
database into my array. =). If you would like to use the code I am putting
it here...
?php
$table = cm_dev_ads;
$dbh = mysql_connect('localhost','user_name','password') or die('Could not
connect to database, please try again later');
mysql_select_db('bignicke') or die('Could not select database, please try
again later');
$record = mysql_query(SELECT wel_area, ad01, ad02, ad03, ad04, ad05, ad06,
ad01_t, ad02_t, ad03_t, ad04_t, ad05_t, ad06_t FROM $table,$dbh);
while ($row = mysql_fetch_array($record)) {
$wel_area = $row['wel_area'];
$ad01 = $row['ad01'];
$ad02 = $row['ad02'];
$ad03 = $row['ad03'];
$ad04 = $row['ad04'];
$ad05 = $row['ad05'];
$ad06 = $row['ad06'];
$ad01_t = $row['ad01_t'];
$ad02_t = $row['ad02_t'];
$ad03_t = $row['ad03_t'];
$ad04_t = $row['ad04_t'];
$ad05_t = $row['ad05_t'];
$ad05_t = $row['ad05_t'];
$ad06_t = $row['ad06_t'];
}
?
That is the db connection and the results put into an array...
?php
require 'db_index.php';
?
This calls to the array script, now to echo them into my java-script it is
as follows...
a href='javascript:openPopWin(?php echo $ad01; ?, 420,545, , 0,
0)'onmouseover=window.status='This weeks full page ad';return trueimg
src=?php echo $ad01_t; ? width=200 height=100 vspace=0 hspace=0
border=0/a
Hope this helps some other people that might want to do the same type of
thing...
Jas
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RE: [PHP] nl2br returns BR /? normality or a bug?
For the record br/ (which would be the 'normal' xhtml style) is unrecognized (and therefor ignored) by Netscape 4.x. However, it recognizes and properly handles br /, which I'm sure is why it is output in that format. If anybody has seen br/ misbehave, try going back and testing with br /. - Theo -Original Message- From: Miguel Cruz [mailto:[EMAIL PROTECTED]] Sent: Saturday, April 06, 2002 1:57 AM To: Justin French Cc: php Subject: Re: [PHP] nl2br returns BR /? normality or a bug? On Sat, 6 Apr 2002, Justin French wrote: on 06/04/02 11:05 AM, Maxim Maletsky ([EMAIL PROTECTED]) wrote: It DOES NOT work fine in every browser. I'd love to give you a prov, but because I am lazy I will just tell you this formula: Again. I was only stating MY experience. Every browser I can get my hands on. I do extensive testing, and have never seen a BR or BR/ or BR / misbehave. If you have seen it perform unexpectedly, I'm keen to hear about. For what it's worth, I just tried on the following browsers (all I have at my disposal at home) and it works fine: links 0.96 lynx 2.8.3 Opera 5.0.498 (Mac) IE 5.1.3 (Mac) Mozilla 0.9.9 (Mac) Netscape 6.1 (Mac) miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Directory check
Le lundi 8 avril 2002, à 04:15 PM, Hiroshi Ayukawa a écrit :
Does anyone know how to check a directory exiasts?
RTFM !!
try this :
if (file_exists($dir) is_dir($dir)) {
echo $dir.' is a directory !';
}
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RE: [PHP] Test for one bit set?
Try a bitwise and (I think the operator is '')...
?php
$bitMask = 16;
$value1 = 24;
$value2 = 36;
?$value1 has bit 5 set? ?php
if($bitMask $value1)
{
//should get here
echo 'true\r\n';
}
else
{
echo 'false\r\n';
}
?$value2 has bit 5 set? ?php
if($bitMask $value1)
{
echo 'true\r\n';
}
else
{
//should get here
echo 'false\r\n';
}
?
- Theo
-Original Message-
From: Miguel Cruz [mailto:[EMAIL PROTECTED]]
Sent: Sunday, April 07, 2002 5:04 PM
To: Charlie Killian
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Test for one bit set?
On Sun, 7 Apr 2002, Charlie Killian wrote:
How can I test if a number only has on bit set?
So testing different numbers will return TRUE or FALSE:
testing 0001 would return TRUE.
testing 0011 would return FALSE.
Think back to math class when you were 14!
function isOneBitSet($n)
{
$x = log($n)/log(2);
return ($x == intval($x));
}
Cheesy alternative:
function isOneBitSet($n)
{
return (1 == substr_count(base_convert($n, 10, 2), '1'));
}
miguel
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RE: [PHP] MAC file upload
Shane, Eric is absolutely right, you are losing the resource fork of your mac binaries when you upload them. (If you don't know, on a Mac, the binary file has to parts, the data, and the association with an application (or resource) that created the file. This is done so that Mac file names don't need an extension) Most server systems (except Mac of course) don't know how to handle a resource fork, so they drop it. The standard Mac work around is to convert the binary file to a text format called binhex (.hqx filename extension) upload the .hqx file to the server and then reconvert it back once downloaded to a Mac that knows what to do with the resource fork information. This process can be automated with apple script if you like, but, if you ever want another machead to help you diagnose problems, stick to this layout, that way they know what you are doing. Rance Rance Hall 308.238.2455 Internal Office Extensions: 2455 or 6655 PC Programmer, The Buckle, Inc. [EMAIL PROTECTED] -Original Message- From: Erik Price [mailto:[EMAIL PROTECTED]] Sent: Monday, April 08, 2002 8:46 AM To: Shane McBride Cc: [EMAIL PROTECTED] Subject: Re: [PHP] MAC file upload On Saturday, April 6, 2002, at 11:44 AM, Shane McBride wrote: Hello, I am able to upload and download Macintosh files but they seem to lose their MIME type or extensions. I'm not sure what it is. I'm not a Mac dude. When you download the file It loses the file association. It's for a company I do work for that uses a lot of .ai and .psd files. Any ideas on this? You're possibly losing the resource fork of the files you are uploading, because the server is not an HFS+ filesystem. To the best of my knowledge there is nothing you can do about this via PHP, but there are probably tricks (like AppleScript) that you could use as a workaround, such as encoding the files in some transport-friendly format before uploading and decoding them upon download. Erik Erik Price Web Developer Temp Media Lab, H.H. Brown [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array elements missing
Can anyone tell me why when the first element in my array would disappear
with the following code:
?
//remove the unwanted item from the array
for($i=0;$icount($stores);$i++) {
$delete=0;
//checking to see if it has been requested for delete
foreach($HTTP_POST_VARS as $val) {
if(is_numeric($val)) {
if($val==$i) $delete = 1;
else continue;
}
else continue;
}
//if not requested for delete, push on to temp array
if($delete == 0) {
array_push($temp, $stores[$i]);
}
}
$stores = $temp;
print_r($stores);
print_r($HTTP_POST_VARS);
?
Here is the output of the print_r's:
Array
(
[0] =
[1] = Array
(
[0] = AR
[1] = 1
[2] = 1059 11th St.
[3] = Grand Rapids
[4] = (233) 457-2394
[5] = (233) 457-4982
[6] =
[7] =
[8] =
)
[2] = Array
(
[0] = AR
[1] = 2
[2] = 1059 11th St.
[3] = Grand Rapids
[4] = (233) 457-2394
[5] = (233) 457-4982
[6] =
[7] =
[8] =
)
[3] = Array
(
[0] = LA
[1] = 3
[2] = 1174 Gernaat Ct.
[3] = Delton
[4] = (233) 457-2394
[5] = (233) 457-4982
[6] =
[7] =
[8] =
)
[4] = Array
(
[0] = ME
[1] = 4
[2] = 1059 11th St.
[3] = Delton
[4] = (233) 457-2394
[5] = (233) 457-4982
[6] =
[7] =
[8] =
)
[5] = Array
(
[0] = MI
[1] = 6
[2] = 437 4th Ave.
[3] = Yet Another City
[4] = (123) 283-4839
[5] = (123) 458-4843
[6] =
[7] =
[8] =
)
)
Array
(
[chk5] = 5
[Submit] = Delete Store(s)
)
The script deletes the element that was requested deleted, but for some
reason the first element in the array never gets copied. Any help that you
can provide would be greatly appreciated.
--
Joshua E Minnie
CIO
[EMAIL PROTECTED]
Don't work for recognition, but always do work worthy of recognition.
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Re: [PHP] mod_php4
Here is what I get when I try to make a DSO with apache 2.0.35 and php 4.1.2: Script started on Sun Apr 7 13:39:30 2002 doctor.nl2k.ab.ca//usr/source/php-4.1.2$ make Making all in Zend Making all in main Making all in ext Making all in zlib Making all in ftp Making all in gd Making all in mysql Making all in openssl Making all in pcre Making all in pcrelib Making all in posix Making all in session Making all in standard Making all in xml Making all in expat Making all in sapi Making all in apache2filter /bin/sh /usr2/source/php-4.1.2/libtool --silent --mode=compile gcc -I. -I/usr2/source/php-4.1.2/sapi/apache2filter -I/usr2/source/php-4.1.2/main -I/usr2/source/php-4.1.2 -I/var/www/include/ -I/usr2/source/php-4.1.2/Zend -I/usr/contrib/include -I/usr2/source/gd-1.8.3 -I/usr/contrib/include/mysql -I/usr2/source/php-4.1.2/ext/xml/expat -I/usr2/source/php-4.1.2/TSRM -g -O2 -DZTS -prefer-pic -c sapi_apache2.c sapi_apache2.c: In function `php_apache_sapi_ub_write': sapi_apache2.c:58: too few arguments to function `apr_brigade_create' sapi_apache2.c:61: too few arguments to function `apr_bucket_transient_create' sapi_apache2.c: In function `php_apache_sapi_register_variables': sapi_apache2.c:148: warning: initialization discards qualifiers from pointer target type sapi_apache2.c: In function `php_apache_sapi_flush': sapi_apache2.c:171: too few arguments to function `apr_brigade_create' sapi_apache2.c:172: too few arguments to function `apr_bucket_flush_create' sapi_apache2.c: In function `php_input_filter': sapi_apache2.c:245: too few arguments to function `apr_brigade_create' sapi_apache2.c:247: incompatible type for argument 4 of `ap_get_brigade' sapi_apache2.c:247: too few arguments to function `ap_get_brigade' sapi_apache2.c: In function `php_output_filter': sapi_apache2.c:311: too few arguments to function `apr_brigade_create' sapi_apache2.c:366: too few arguments to function `apr_bucket_transient_create' sapi_apache2.c:375: too few arguments to function `apr_bucket_eos_create' sapi_apache2.c: In function `php_register_hook': sapi_apache2.c:407: `AP_FTYPE_CONTENT' undeclared (first use in this function) sapi_apache2.c:407: (Each undeclared identifier is reported only once sapi_apache2.c:407: for each function it appears in.) sapi_apache2.c:408: warning: passing arg 2 of `ap_register_input_filter' from incompatible pointer type *** Error code 1 Stop. *** Error code 1 Stop. *** Error code 1 Stop. *** Error code 1 Stop. doctor.nl2k.ab.ca//usr/source/php-4.1.2$ exit exit Script done on Sun Apr 7 13:39:58 2002 -- Member - Liberal International On 11 Sept 2001 the WORLD was violated. This is [EMAIL PROTECTED] Ici [EMAIL PROTECTED] Society MUST be saved! Extremists must dissolve. Beware of defining as intelligent only those who share your opinions -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Appending url to file name...
Ok this is an unusual problem, at least to a newbie like myself... I am
trying to develop a user form to select an image from a directory by use of
a select box that once the item is selected it will put that selection into
a db field and this part I have working fine, however now I will need to be
able to do something which I am not entirely clear on where to start...
1- I need to have the selection append the file path to the selected file...
i.e. http://localhost/images/file_name.jpg, so far it only puts
file_name.jpg into the database table.
My code is as follows:
Page 1- index.php (queries database to display current db contents and also
queries directory and places results into an array that is displayed in a
select box)
?php
$dir_name = /path/to/images/directory/on/server/;
$dir = opendir($dir_name);
$file_list .= pFORM METHOD=\post\ ACTION=\index_done.php3\
SELECT NAME=\files\;
while ($file_name = readdir($dir)) {
if (($file_name != .) ($file_name !=..)) {
$file_list .= OPTION VALUE=\$file_name\
NAME=\$file_name\$file_name/OPTION;
}
}
$file_list .= /SELECTbrbrINPUT TYPE=\submit\ NAME=\submit\
VALUE=\select\/FORM/p;
closedir($dir);
$table = table_nae;
$dbh = mysql_connect('localhost','user_name','password') or die('Could not
connect to database, please try again later');
mysql_select_db('db_name') or die('Could not select database, please try
again later');
$record = mysql_query(SELECT wel_area, ad01_t, ad01, ad02_t, ad02, ad03_t,
ad03, ad04_t, ad04, ad05_t, ad05, ad06_t, ad06 FROM $table,$dbh);
while ($row = mysql_fetch_array($record)) {
list($wel_area, $ad01_t, $ad01, $ad02_t, $ad02, $ad03_t, $ad03, $ad04_t,
$ad04, $ad05_t, $ad05, $ad06_t, $ad06) = $row;
}?
This echoes the resulting directory into my select box...
? echo $file_list; ?
And this will echo the existing db entry...
img src=?php echo $ad01_t; ? width=200 height=100 vspace=0
hspace=0 border=0
Ok so far so good, now the items that are selected from the drop box need to
somehow (this is where I am stuck append the file path, i.e. the complete
url to the db entry and I am not quite sure how to accomplish this, if
anyone has a tutorial or even an example to show me I can figure it out from
there... this is the piece of code I am using on the index_done.php3 file.
?php
$db_name = db_name;
$table_name = table_name;
$connection = mysql_connect(localhost, user_name, password) or die
(Could not connect to database. Please try again later.);
$db = mysql_select_db($db_name,$connection) or die (Could not select
database table. Please try again later.);
$sql = UPDATE $table_name SET ad01_t=\$files;
print $sql;
$result = mysql_query($sql, $connection) or die (Could not execute query.
Please try again later.);
?
Any help would be great...
Jas
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[PHP] Re: what's the best way to do redirect within PHP
Dear All, Thanks for all the response, they all work! --Wo - Original Message - From: Wo Chang [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, April 08, 2002 10:00 AM Subject: what's the best way to do redirect within PHP Dear All, Another simple question: What is the best way to do redirect after a php file did some processing? Any helps would be greatly appreciated! --Wo -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Adding Querystrings to links
Hi all! I have a problem with the querystring.I want to add to every Link on my Homepage a querystring, but i should have the possibility to change some details in the Querystring. How should i solve this problem ? Example : http://domain.com/index.php?dest=12item=2 The variables ?dest= and item= should be in every Link on my site.But only the values 12 and 2 should be alterable. Thank you,and sorry for my bad english Chris
Re: [PHP] Re: php and html image tag...
I don't know if anybody else sent you an email about this or not, but
there's a much easier way to do what you're doing in this snippet of code...
$record = mysql_query(SELECT wel_area, ad01, ad02, ad03, ad04, ad05,
ad06, ad01_t, ad02_t, ad03_t, ad04_t, ad05_t, ad06_t FROM $table,$dbh);
while ($row = mysql_fetch_array($record)) {
// this should print no
print( wel_areas set: . ( isset( $wel_areas ) ? Yes : No ));
extract( $row );
// this should print yes
print( wel_areas set: . ( isset( $wel_areas ) ? Yes : No ));
}
this will create variables into the local scope of each element in this
associative array. It's a lot easier than typing each assignment out, and
it also means if you include a new field in your query, your code will not
have to create a new variable, it'll be automatic...
At 08:29 AM 4/8/2002 -0600, Jas wrote:
Nevermind I got it fixed... I forgot to include a couple of fields from my
database into my array. =). If you would like to use the code I am putting
it here...
?php
$table = cm_dev_ads;
$dbh = mysql_connect('localhost','user_name','password') or die('Could not
connect to database, please try again later');
mysql_select_db('bignicke') or die('Could not select database, please try
again later');
$record = mysql_query(SELECT wel_area, ad01, ad02, ad03, ad04, ad05, ad06,
ad01_t, ad02_t, ad03_t, ad04_t, ad05_t, ad06_t FROM $table,$dbh);
while ($row = mysql_fetch_array($record)) {
$wel_area = $row['wel_area'];
$ad01 = $row['ad01'];
$ad02 = $row['ad02'];
$ad03 = $row['ad03'];
$ad04 = $row['ad04'];
$ad05 = $row['ad05'];
$ad06 = $row['ad06'];
$ad01_t = $row['ad01_t'];
$ad02_t = $row['ad02_t'];
$ad03_t = $row['ad03_t'];
$ad04_t = $row['ad04_t'];
$ad05_t = $row['ad05_t'];
$ad05_t = $row['ad05_t'];
$ad06_t = $row['ad06_t'];
}
?
That is the db connection and the results put into an array...
?php
require 'db_index.php';
?
This calls to the array script, now to echo them into my java-script it is
as follows...
a href='javascript:openPopWin(?php echo $ad01; ?, 420,545, , 0,
0)'onmouseover=window.status='This weeks full page ad';return trueimg
src=?php echo $ad01_t; ? width=200 height=100 vspace=0 hspace=0
border=0/a
Hope this helps some other people that might want to do the same type of
thing...
Jas
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Re: [PHP] Appending url to file name...
On Monday, April 8, 2002, at 11:09 AM, Jas wrote:
Ok this is an unusual problem, at least to a newbie like myself... I am
trying to develop a user form to select an image from a directory by
use of
a select box that once the item is selected it will put that selection
into
a db field and this part I have working fine, however now I will need
to be
able to do something which I am not entirely clear on where to start...
1- I need to have the selection append the file path to the selected
file...
i.e. http://localhost/images/file_name.jpg, so far it only puts
file_name.jpg into the database table.
If you already know that the file will always be in the same directory,
you could just prepend the string http://localhost/images/; to the
query result in your query --
SELECT CONCAT('http://localhost/images/', tablename.image_name) AS
image_name FROM tablename
Or, if each file may have a different path, check out the dirname()
function -- http://www.php.net/manual/en/function.dirname.php
I think that you will have to add http://virtualhost; in any case, as
this is a component of a URI and not a part of the file's path (and will
not be automatically generated by dirname() or any other function that I
know of).
Erik
Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]
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[PHP] Re: Directory check
try:
if(is_dir($dir)) {
echo 'directory was found';
}
Yoroshiku,
Maxim Maletsky
PHPBeginner.com
Hiroshi Ayukawa writes:
Does anyone know how to check a directory exiasts?
Thanks in advance,
Hiroshi Ayukawa
http://hoover.ktplan.ne.jp/kaihatsu/php_en/index.php?type=top
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Maxim Maletsky
Founder, Chief Developer
PHPBeginner.com (Where PHP Begins)
www.PHPBeginner.com
[EMAIL PROTECTED]
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RE: [PHP] Adding Querystrings to links
you want to try a code line like this
print a
href=\yourpagehere.phtml?dest=$line[index]item=$line[index2]\LinkName/a;
it will only work of course if you are in the middle of a loop that processes the
results of an appropriate select statement that pulls the needed values for your dest
and item variables.
for a similar project I wrote this:
for ($i=0; $i $rowcount; $i++) {
$line = mysql_fetch_array($results);
if ($i % 2) {
print tr bgcolor=\white\\n;
}
else {
print tr bgcolor=\#e0e0e0\\n;
}
print tda
href=\project_details.phtml?project=$line[pk]\$line[projectname]/a/td\n;
print td$line[projectcustomer]/td\n;
print td$line[projectstatus]/td\n;
print td$line[projectcompletion]%/td\n;
print /tr\n;
}
Hope it helps
Rance Hall
308.238.2455
Internal Office Extensions: 2455 or 6655
PC Programmer, The Buckle, Inc.
[EMAIL PROTECTED]
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Monday, April 08, 2002 10:12 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Adding Querystrings to links
Hi all!
I have a problem with the querystring.I want to add to every Link on my Homepage a
querystring, but i should have the possibility to change some details in the
Querystring.
How should i solve this problem ?
Example :
http://domain.com/index.php?dest=12item=2
The variables ?dest= and item= should be in every Link on my site.But only the
values 12 and 2 should be alterable.
Thank you,and sorry for my bad english
Chris
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[PHP] Besy way to ban a user?
We've used email ban and IP ban but there are easy ways around this as you all know. I am wondering if there is anything a little more hardcore to do as far as banning goes. I had read somewhere about grabbing a MAC address or something similar from a network card. Has anyone heard of this method or does anyone already use a pretty solid method? Jeff -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] SSL needed for socket communication?
My Apache server is currently not configured to use SSL, and I do not have a certificate. There is a possibility that I will be creating a script to send POST data to another company's web service, and that company requires the connection to be via SSL. The logical way for me to do this seems to be to use a socket to fire off the POST data at the other server, but I am not sure what is required to connect via SSL. Since browsers can do it without certificates, I would assume that I don't need a certificate to do this (only for if I want to use SSL with clients connecting to my server), but if someone could confirm this and/or point me in the direction of the functions that allow me to use SSL that would be greatly appreciated. Erik Erik Price Web Developer Temp Media Lab, H.H. Brown [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Appending url to file name...
So putting it into an UPDATE statement it would be something like this
right?
UPDATE CONCAT $table_name SET ('http://localhost/images') ad01=\$ad01\;
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Re: [PHP] Problems with libgd.so under linux
[EMAIL PROTECTED] skrev i meddelandet [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... At 08.04.2002 14:56, you wrote: Php works in general (phpinfo()). The gd-lib however will not work for some reason. I tried extension=libgd.so in php.ini without any result. Anyone familiar with this problem? /M Green Too few arguments ;-) Did you already compiled GD ? Did you compile php with gd support? Oliver I just followed the instructions on php.net for apache servers and changed php.ini. http://www.php.net/manual/en/html/install.apache.html Is there any way to check php.ini for errors? Yeah, one more thing, i moved libphp.so to /etc/httpd/modules to get it to work. So phpinfo(); works fine. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] difficulty in solving the unknown warning
so what does line 111 look like? we can't read your mind... -Original Message- From: erich [mailto:[EMAIL PROTECTED]] Sent: Monday, April 08, 2002 3:35 AM To: [EMAIL PROTECTED] Subject: [PHP] difficulty in solving the unknown warning i am a php programmer whose learning expr. is about 2 months. whatever running script of php that written by other php programmer or me, i always see the warning below shown, why this occurs? how to avoid? Warning: Undefined variable: HTTP_VIA in g:\wwwroot\phpformmail\formmail.php on line 111 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Custom Error Handling
Is there any reason the following code should not work?
I define the error function, then tell PHP to use it, then call
a function which doesn't exist (test), and it will print the error
on screen that that function doesn't exist, but it won't alert me,
so it's obviously not entering the catchError function, why?
?php
function catchError($num, $string, $file, $line)
{
echo script language=\javascript\alert('$num:$string:$file:$line');/script;
}
set_error_handler(catchError);
test();
?
Thanks for your help,
Adam Voigt
[EMAIL PROTECTED]
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Re: [PHP] SSL needed for socket communication?
On Mon, 8 Apr 2002, Erik Price wrote: My Apache server is currently not configured to use SSL, and I do not have a certificate. There is a possibility that I will be creating a script to send POST data to another company's web service, and that company requires the connection to be via SSL. The logical way for me to do this seems to be to use a socket to fire off the POST data at the other server, but I am not sure what is required to connect via SSL. Since browsers can do it without certificates, I would assume that I don't need a certificate to do this (only for if I want to use SSL with clients connecting to my server), but if someone could confirm this and/or point me in the direction of the functions that allow me to use SSL that would be greatly appreciated. While it's possible that the HTTPS server is configured to require client certificates, generally that's not the case. Configuring Apache for SSL has nothing to do with the ability of PHP on that server to make outgoing HTTPS connections to other servers. In my experience the best way to make HTTPS connections from PHP is using cURL. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Besy way to ban a user?
On Mon, 8 Apr 2002, Jeff Lewis wrote: We've used email ban and IP ban but there are easy ways around this as you all know. I am wondering if there is anything a little more hardcore to do as far as banning goes. I had read somewhere about grabbing a MAC address or something similar from a network card. Has anyone heard of this method or does anyone already use a pretty solid method? You shouldn't be able to get the MAC address off someone's card via their web browser (maybe if they allow ActiveX and use Windows then there's some security hole you could exploit). In any case, MACs can be changed, and they still identify a piece of hardware rather than a human. It is a fact of life that things uniquely identifying humans are fairly difficult to validate on the internet. The easier it is to verify, the easier it is to fake. This sometimes-annoying reality is what preserves whatever lingering privacy we still enjoy. Maybe you can cook up a cocktail of cookies, IP, $HTTP_USER_AGENT, and JavaScript-reported browser characteristics. But ultimately you're not going to keep out the determined prankster unless you rely on something that has significance in the Real World, such as credit cards, phone numbers, personal referrals, reputation-based credentials, and so on. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Directory check
On Monday 08 April 2002 22:15, Hiroshi Ayukawa wrote: Does anyone know how to check a directory exiasts? Thanks in advance, Hiroshi Ayukawa http://hoover.ktplan.ne.jp/kaihatsu/php_en/index.php?type=top Manual Filesystem functions -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* When the revolution comes, count your change. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Appending url to file name...
On Monday, April 8, 2002, at 11:35 AM, Jas wrote:
So putting it into an UPDATE statement it would be something like this
right?
UPDATE CONCAT $table_name SET ('http://localhost/images')
ad01=\$ad01\;
No, like this:
The table is named test_table
The column you want to add this to is named test_column
You are taking the data that test_column contains, and prepending
http://localhost/images; to the beginning of that data:
UPDATE test_table SET test_column = CONCAT('http://localhost/images',
test_table.test_column)
Warning: This command will change every single row in your table so that
'http://localhost/images' will be prepended before whatever data is
already in that row. You probably want to make ABSOLUTELY SURE that
this is what you want (are you sure you don't want a trailing slash in
that CONCAT function?). If you want to just test this out, or don't
want to apply this change to EVERY row, you can add a WHERE clause to
choose certain rows to update.
Keep in mind that test_column must be able to accommodate the new string
(so you might need to make it a bigger VARCHAR or something).
Good luck,
Erik
Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]
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[PHP] how to check if e- mail sending did succeed?
Hi there, I use the function mail to e-mail . This workes fine with most adresses. Unfortunatelly there is one e-mail provider (gmx.de) which does not get anny of those e-mails. Workes fine with all other services. I doubble checked it with 2 other gmx accounts. How can I find out what went wrong? Thanx for any help, Andy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] how to check if e- mail sending did succeed?
On Mon, 8 Apr 2002, andy wrote: I use the function mail to e-mail . This workes fine with most adresses. Unfortunatelly there is one e-mail provider (gmx.de) which does not get anny of those e-mails. Workes fine with all other services. I doubble checked it with 2 other gmx accounts. How can I find out what went wrong? Check /var/log/maillog on the server? miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Adding Querystrings to links
On Monday, April 8, 2002, at 11:12 AM, [EMAIL PROTECTED] wrote: I have a problem with the querystring.I want to add to every Link on my Homepage a querystring, but i should have the possibility to change some details in the Querystring. How should i solve this problem ? Example : http://domain.com/index.php?dest=12item=2 The variables ?dest= and item= should be in every Link on my site.But only the values 12 and 2 should be alterable. Here is an example: $destination = 12; $item = 12; // later in the script print(a href=\http://domain.com/index.php?dest=$destinationitem=$item\;Link/a ); Erik Erik Price Web Developer Temp Media Lab, H.H. Brown [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Appending url to file name...
Actually, I tried it a different way and I got the results I needed... this is what I did, $file_var = http://www.bignickel.net/full_ad/;; $db_name = db_name; $table_name = table_name; $connection = mysql_connect(localhost, user_name, password) or die (Could not connect to database. Please try again later.); $db = mysql_select_db($db_name,$connection) or die (Could not select database table. Please try again later.); $sql = UPDATE $table_name SET ad01_t=\$file_var$files\; //this gave me the results, as you can see I just created a new variable with the path in it print $sql; $result = mysql_query($sql, $connection) or die (Could not execute query. Please try again later.); ? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Appending url to file name...
On Mon, 8 Apr 2002, Jas wrote: $sql = UPDATE $table_name SET ad01_t=\$file_var$files\; Is this really what you wanted? It would set ad01_t to the same thing for every single row in your table. If that is what you wanted, then I think your database design is a little weird. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Question
Rather than executing a system utility you can just use the built in PHP functions. gethostbyaddr() - resolves an IP address into a hostname gethostbyname() - resolves hostname into an IP address More information is available in the PHP manual, you can access it online at http://www.php.net/manual Jason -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: Monday, April 08, 2002 6:50 AM To: [EMAIL PROTECTED] Subject: Re: [PHP] Question At 08.04.2002 13:00, you wrote: How to convert or discover from IPadress country visitors on my web ? roman You have to make a DNSLOOKUP If you have a linux box (server setup) you can use system(nslookup -timeout=3 -retry=1 .$value) where $value is the IP-Number. This gives you the real name of the server your client asked from. the you have to extract the national-code, and got your country, or org, mil, com HTH Oliver -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Adding Querystrings to links
Chris, What really matters is where the variables are coming from. print (http://domain.com/index.php?dest=; . $var1 . item= . $var2 .br\n); that's how I usually do it. I'm assuming that both dest and item are variables on the referring page. Reply and let me know if this is what you're looking for. -Jordan K. Martin --New Image Design ---http://www.newimagedesign.com [EMAIL PROTECTED] wrote in message 002f01c1df0f$cb2ef400$0100a8c0@pent333">news:002f01c1df0f$cb2ef400$0100a8c0@pent333... Hi all! I have a problem with the querystring.I want to add to every Link on my Homepage a querystring, but i should have the possibility to change some details in the Querystring. How should i solve this problem ? Example : http://domain.com/index.php?dest=12item=2 The variables ?dest= and item= should be in every Link on my site.But only the values 12 and 2 should be alterable. Thank you,and sorry for my bad english Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Question
How does that tell you where something is? Quick quiz, some obvious high-profile examples off the top of my head: netvigator.com ntlworld.com bigpond.net chello.com unicc.org miguel On Mon, 8 Apr 2002, SHEETS,JASON (Non-HP-Boise,ex1) wrote: Rather than executing a system utility you can just use the built in PHP functions. gethostbyaddr() - resolves an IP address into a hostname gethostbyname() - resolves hostname into an IP address More information is available in the PHP manual, you can access it online at http://www.php.net/manual Jason -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: Monday, April 08, 2002 6:50 AM To: [EMAIL PROTECTED] Subject: Re: [PHP] Question At 08.04.2002 13:00, you wrote: How to convert or discover from IPadress country visitors on my web ? roman You have to make a DNSLOOKUP If you have a linux box (server setup) you can use system(nslookup -timeout=3 -retry=1 .$value) where $value is the IP-Number. This gives you the real name of the server your client asked from. the you have to extract the national-code, and got your country, or org, mil, com HTH Oliver -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Phone number validation
try this preg_match(/[a-zA-Z]+/i, $str); and if you want to go the other route. do this preg_match(/[^0-9\(\)\-\.\ ]+/i, $str); this will return true if it is anything other then what is listed. numbers 0-9 ( ) - . Jim Lucas - Original Message - From: Gary [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Saturday, April 06, 2002 6:52 PM Subject: [PHP] Phone number validation Hi All, I tried to cut a corner and use an alphabetic validation I am using elsewhere $stuff = /^[a-zA-Z]+$/; if(preg_match($stuff, $value)) looks like I forgot about +( )- being in phone number. What is the easiest way to allow these 4 characters? Are there any other characters that people use? TIA Gary -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] counter for HIGH traffic site
as long as you are only inserting information into the mysql db on each page load, then you shouldn't have a problem. make sure you keep you indecies down to a minimum. Jim Lucas - Original Message - From: Craig Westerman [EMAIL PROTECTED] To: php-general-list [EMAIL PROTECTED] Sent: Saturday, April 06, 2002 11:57 PM Subject: [PHP] counter for HIGH traffic site I'm needing counter for site that receives 60 to 80 hits a minute. Many I have tried cause excessive server load and need to be deactivated or they lose data and return to zero without warning. All tried so far have been written in Perl. Anyone here know of a PHP counter that would handle HIGH traffic with little added server load? Would using MySQL to store count be of any benifit? Thanks Craig [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Object Confusion
If object of type A ($A) contains a variable $B which is an object of type B, how does a function within $B reference another variable in $A? Thanks.
[PHP] Assigning unique form names...
Here is what I need some information about, the script below opens a
directory on the server, reads the files and places them into select boxes
within a form, now I have this echoed multiple times on the page like
so...? echo $file_list; ? Now I have tried to assign a form name based
on the $file_name varibable but because the $file_name variable is created
after the form has been created I cannot assign a unique form name each time
I call ? echo $file_list; ?. If someone could point out another way to
do this or point out a good function for this I would greatly appreciate it.
?php
$dir_name = /path/to/images/directory/;
$dir = opendir($dir_name);
$file_list .= pFORM METHOD=\post\ ACTION=\index_done.php3\
SELECT NAME=\files\;
while ($file_name = readdir($dir)) {
if (($file_name != .) ($file_name !=..)) {
$file_list .= OPTION VALUE=\$file_name\
NAME=\$file_name\$file_name/OPTION;
}
}
$file_list .= /SELECTbrbrINPUT TYPE=\submit\ NAME=\submit\
VALUE=\select\/FORM/p;
closedir($dir);
?
Thanks in advance,
Jas
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RE: [PHP] Assigning unique form names...
Try select name=files[] The square brackets will allow you to
capture selections from multiple lists in an indexed array, $files.
Hope that does what you need.
-Kevin
The square brackets will allow you to capture the variable $file_name
-Original Message-
From: Jas [mailto:[EMAIL PROTECTED]]
Sent: Monday, April 08, 2002 10:59 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Assigning unique form names...
Here is what I need some information about, the script below opens a
directory on the server, reads the files and places them into select
boxes
within a form, now I have this echoed multiple times on the page like
so...? echo $file_list; ? Now I have tried to assign a form name
based
on the $file_name varibable but because the $file_name variable is
created
after the form has been created I cannot assign a unique form name each
time
I call ? echo $file_list; ?. If someone could point out another way
to
do this or point out a good function for this I would greatly appreciate
it.
?php
$dir_name = /path/to/images/directory/;
$dir = opendir($dir_name);
$file_list .= pFORM METHOD=\post\ ACTION=\index_done.php3\
SELECT NAME=\files\;
while ($file_name = readdir($dir)) {
if (($file_name != .) ($file_name !=..)) {
$file_list .= OPTION VALUE=\$file_name\
NAME=\$file_name\$file_name/OPTION;
}
}
$file_list .= /SELECTbrbrINPUT TYPE=\submit\ NAME=\submit\
VALUE=\select\/FORM/p;
closedir($dir);
?
Thanks in advance,
Jas
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[PHP] Upload alert
Hi! I need a php script to alert me (with a pop up window or something like that) when a certain web page is modified. Is it possible? Where can I find that? Tks in advance, Rodolfo Silva -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
