Re[2]: [PHP] How to list 2-6 in while script?

2001-09-12 Thread Andrew Perevodchik 

Hello! You wrote:

 Hi! I have this script and wonder how to change
 it to get it list only number 2 to number 6 and
 not each?

 while (list ($key,$val) = each ($headers)) {
 print pb.$val./b/p;
  }

while (list ($key,$val) = each ($headers) and
   $key = 6 and
   $key = 2) {

   print pb.$val./b/p;
}

Eh?

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Re: [PHP] How to list 2-6 in while script?

2001-09-12 Thread Alexander Skwar 

So sprach »Andrew Perevodchik« am 2001-09-12 um 14:45:25 +0300 :
 Hello! You wrote:
 
  Hi! I have this script and wonder how to change
  it to get it list only number 2 to number 6 and
  not each?
 
  while (list ($key,$val) = each ($headers)) {
  print pb.$val./b/p;
   }
 
 while (list ($key,$val) = each ($headers) and
$key = 6 and
$key = 2) {
 
print pb.$val./b/p;
 }
 
 Eh?

Oh, if $key contains the number, than yes.  I understood his question
differently.

Alexander Skwar
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[PHP] How to list 2-6 in while script?

2001-09-11 Thread Jan Grafström 

Hi!
I have this script and wonder how to change it to get it list only number 2 to number 
6 and 
not each?
while (list ($key,$val) = each ($headers)) {
print pb.$val./b/p;
 }
Thanks in advance.
Regards
Jan


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Re: [PHP] How to list 2-6 in while script?

2001-09-11 Thread Alexander Skwar 

So sprach »Jan Grafström« am 2001-09-11 um 16:48:59 + :
 Hi!
 I have this script and wonder how to change it to get it list only number 2 to 
number 6 and 
 not each?
 while (list ($key,$val) = each ($headers)) {
 print pb.$val./b/p;
  }

Hmm
$i = 1;
while (list ($key,$val) = each ($headers)){
if (2 == $i || 6 == $i){
continue;
}
print $val;
$i++;
}
Alexander Skwar
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