Yes thanks for that, I already have this but am having a brain cramp on how
to obtain years.
function datediff($now, $old)
{
/
$DIS = $now - $old; // Diff In Secs
$secs = $DIS % 60; // modulo
$DIS -= $secs;
$days = floor($DIS / (24*60*60));
$DIS -= $days * (24*60*60);
$hours = floor($DIS / (60*60));
$DIS -= $hours * (60*60);
$mins = floor($DIS / 60);
$DIS -= $mins * 60;
$diffstr= $days Days, $hours Hours, $mins Minutes, $secs Seconds;
return $days;
}
- Original Message -
From: Jack Dempsey [EMAIL PROTECTED]
To: Jeff Lewis [EMAIL PROTECTED]; PHP is not a drug.
[EMAIL PROTECTED]
Sent: Saturday, November 17, 2001 3:30 PM
Subject: RE: [PHP] Converting dates?
search the archives there are tons of messages dealing with date
manipulation.
basically take the timestamps find the difference in seconds, convert to
days, etc
jack
-Original Message-
From: Jeff Lewis [mailto:[EMAIL PROTECTED]]
Sent: Saturday, November 17, 2001 3:17 PM
To: PHP is not a drug.
Subject: [PHP] Converting dates?
I am storing a birthdate in my database as a Unix timestamp but when I
display it I want to calculate the different between that date and todays
date and display the persons age.
How can I do that with PHP?
I also want to know if it is currently their birthday. So trying to set
$isbday to yes if todays month and day are the same as their birthdate in
the database.
Jeff
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