May be this helps:
l1- list('a',1)
l2- list('b',2)
l3- list('c',3)
df1-data.frame(mapply(`c`,l1,l2,l3,SIMPLIFY=FALSE),stringsAsFactors=FALSE)
colnames(df1)-paste0(X,1:2)
str(df1)
#'data.frame': 3 obs. of 2 variables:
# $ X1: chr a b c
# $ X2: num 1 2 3
A.K.
- Original Message -
From: Shaun Jackman sjack...@gmail.com
To: R help r-help@r-project.org
Cc:
Sent: Wednesday, July 31, 2013 5:58 PM
Subject: [R] Convert rbind of lists to data.frame
I'm trying to build a data.frame row-by-row like so:
df - data.frame(rbind(list('a',1), list('b', 2), list('c', 3)))
I was surprised to see that the columns of the resulting data.frame
are stored in lists rather than vectors.
str(df)
'data.frame': 3 obs. of 2 variables:
$ X1:List of 3
..$ : chr a
..$ : chr b
..$ : chr c
$ X2:List of 3
..$ : num 1
..$ : num 2
..$ : num 3
The desired result is:
str(df)
'data.frame': 3 obs. of 2 variables:
$ X1: chr a b c
$ X2: num 1 2 3
The following works, but is rather ugly:
df - data.frame(lapply(data.frame(rbind(list('a',1), list('b', 2),
list('c', 3))), unlist))
Thanks,
Shaun
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and provide commented, minimal, self-contained, reproducible code.