[symfony-users] Re: How to access the object of an embedded form
Perfect! Works like a charm. Looking forward to sf1.3 to get rid of the
need for the work-around.
Tom Haskins-Vaughan wrote:
Thanks, esion. I'll give it a go and let you know how I get on.
esion wrote:
Hi,
First, I'm not sure that works :
?php foreach($form as $cartItemForm): ?
tr
td?php echo $cartItemForm['quantity']-renderLabel() ?/
td
td?php echo $cartItemForm['quantity'] ?/td
td/td
/tr
?php endforeach; ?
It doesn't match with what you wrote in your form, what do you have in
your action file?
You should have in your view something like that :
?php foreach($form-getEmbeddedForms() as $cartItemForm): ?
tr
td colspan=2?php echo $cartItemForm ?/td
/tr
?php enforeach ?
Second (this is a really special gift, I spend several weeks to find
this tricks on the net, so I'm waiting for sf1.3
http://trac.symfony-project.org/ticket/5264)
If you want to design your embedded forms you should use this code in
the foreach :
$nameFormat = $form-getWidgetSchema()-generateName($name) .
'[%s]';
$cartItemForm-getWidgetSchema()-setNameFormat($nameFormat);
else the name used in fields will be the same, then the form can't
work.
Then you have now your array of sfForm, you can get the embedded forms
of the embedded form.
$cartItemForm-getEmbeddedForms()
On May 21, 8:33 pm, Tom Haskins-Vaughan t...@templestreetmedia.com
wrote:
Hi,
I have successfully embedded a form like so:
class CartForm extends BaseCartForm
{
public function configure()
{
unset(
$this['id'],
$this['is_default'],
$this['buyer_id']
);
foreach($this-getObject()-getCartItems() as $cartItem)
{
$this-embedForm(
'cartitem_'.$cartItem-cart_id.'_'.$cartItem-harvest_id,
new CartItemForm($cartItem)
);
}
}
}
And I have managed to display it like so:
form method=post action=?php echo url_for('@my_cart') ?
tbody
?php foreach($form as $cartItemForm): ?
tr
td?php echo $cartItemForm['quantity']-renderLabel() ?/td
td?php echo $cartItemForm['quantity'] ?/td
td/td
/tr
?php endforeach; ?
/tbody
/table
input type=submit value=Update cart /
/form
But I need to access some more information about each CartItem to
display in the form, such as the Producer
($cartItem-Harvest-Producer). But in my example, it seems that
$cartItemForm is not an sfForm but a sfFormField. So how do I access the
Object of a form from a form field?
Any help much appreciated.
Thanks
Tom
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[symfony-users] Re: How to access the object of an embedded form
Thanks, esion. I'll give it a go and let you know how I get on.
esion wrote:
Hi,
First, I'm not sure that works :
?php foreach($form as $cartItemForm): ?
tr
td?php echo $cartItemForm['quantity']-renderLabel() ?/
td
td?php echo $cartItemForm['quantity'] ?/td
td/td
/tr
?php endforeach; ?
It doesn't match with what you wrote in your form, what do you have in
your action file?
You should have in your view something like that :
?php foreach($form-getEmbeddedForms() as $cartItemForm): ?
tr
td colspan=2?php echo $cartItemForm ?/td
/tr
?php enforeach ?
Second (this is a really special gift, I spend several weeks to find
this tricks on the net, so I'm waiting for sf1.3
http://trac.symfony-project.org/ticket/5264)
If you want to design your embedded forms you should use this code in
the foreach :
$nameFormat = $form-getWidgetSchema()-generateName($name) .
'[%s]';
$cartItemForm-getWidgetSchema()-setNameFormat($nameFormat);
else the name used in fields will be the same, then the form can't
work.
Then you have now your array of sfForm, you can get the embedded forms
of the embedded form.
$cartItemForm-getEmbeddedForms()
On May 21, 8:33 pm, Tom Haskins-Vaughan t...@templestreetmedia.com
wrote:
Hi,
I have successfully embedded a form like so:
class CartForm extends BaseCartForm
{
public function configure()
{
unset(
$this['id'],
$this['is_default'],
$this['buyer_id']
);
foreach($this-getObject()-getCartItems() as $cartItem)
{
$this-embedForm(
'cartitem_'.$cartItem-cart_id.'_'.$cartItem-harvest_id,
new CartItemForm($cartItem)
);
}
}
}
And I have managed to display it like so:
form method=post action=?php echo url_for('@my_cart') ?
tbody
?php foreach($form as $cartItemForm): ?
tr
td?php echo $cartItemForm['quantity']-renderLabel() ?/td
td?php echo $cartItemForm['quantity'] ?/td
td/td
/tr
?php endforeach; ?
/tbody
/table
input type=submit value=Update cart /
/form
But I need to access some more information about each CartItem to
display in the form, such as the Producer
($cartItem-Harvest-Producer). But in my example, it seems that
$cartItemForm is not an sfForm but a sfFormField. So how do I access the
Object of a form from a form field?
Any help much appreciated.
Thanks
Tom
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[symfony-users] Re: How to access the object of an embedded form
Hi,
First, I'm not sure that works :
?php foreach($form as $cartItemForm): ?
tr
td?php echo $cartItemForm['quantity']-renderLabel() ?/
td
td?php echo $cartItemForm['quantity'] ?/td
td/td
/tr
?php endforeach; ?
It doesn't match with what you wrote in your form, what do you have in
your action file?
You should have in your view something like that :
?php foreach($form-getEmbeddedForms() as $cartItemForm): ?
tr
td colspan=2?php echo $cartItemForm ?/td
/tr
?php enforeach ?
Second (this is a really special gift, I spend several weeks to find
this tricks on the net, so I'm waiting for sf1.3
http://trac.symfony-project.org/ticket/5264)
If you want to design your embedded forms you should use this code in
the foreach :
$nameFormat = $form-getWidgetSchema()-generateName($name) .
'[%s]';
$cartItemForm-getWidgetSchema()-setNameFormat($nameFormat);
else the name used in fields will be the same, then the form can't
work.
Then you have now your array of sfForm, you can get the embedded forms
of the embedded form.
$cartItemForm-getEmbeddedForms()
On May 21, 8:33 pm, Tom Haskins-Vaughan t...@templestreetmedia.com
wrote:
Hi,
I have successfully embedded a form like so:
class CartForm extends BaseCartForm
{
public function configure()
{
unset(
$this['id'],
$this['is_default'],
$this['buyer_id']
);
foreach($this-getObject()-getCartItems() as $cartItem)
{
$this-embedForm(
'cartitem_'.$cartItem-cart_id.'_'.$cartItem-harvest_id,
new CartItemForm($cartItem)
);
}
}
}
And I have managed to display it like so:
form method=post action=?php echo url_for('@my_cart') ?
tbody
?php foreach($form as $cartItemForm): ?
tr
td?php echo $cartItemForm['quantity']-renderLabel() ?/td
td?php echo $cartItemForm['quantity'] ?/td
td/td
/tr
?php endforeach; ?
/tbody
/table
input type=submit value=Update cart /
/form
But I need to access some more information about each CartItem to
display in the form, such as the Producer
($cartItem-Harvest-Producer). But in my example, it seems that
$cartItemForm is not an sfForm but a sfFormField. So how do I access the
Object of a form from a form field?
Any help much appreciated.
Thanks
Tom
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symfony users group.
To post to this group, send email to symfony-users@googlegroups.com
To unsubscribe from this group, send email to
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[symfony-users] Re: How to access the object of an embedded form
Oups, another tip :
Don't forget that echo $form will display all the form and embedded
ones, It's really helpfull to design forms.
Cheers,
David.
On May 23, 11:26 am, esion esio...@gmail.com wrote:
Hi,
First, I'm not sure that works :
?php foreach($form as $cartItemForm): ?
tr
td?php echo $cartItemForm['quantity']-renderLabel() ?/
td
td?php echo $cartItemForm['quantity'] ?/td
td/td
/tr
?php endforeach; ?
It doesn't match with what you wrote in your form, what do you have in
your action file?
You should have in your view something like that :
?php foreach($form-getEmbeddedForms() as $cartItemForm): ?
tr
td colspan=2?php echo $cartItemForm ?/td
/tr
?php enforeach ?
Second (this is a really special gift, I spend several weeks to find
this tricks on the net, so I'm waiting for
sf1.3http://trac.symfony-project.org/ticket/5264)
If you want to design your embedded forms you should use this code in
the foreach :
$nameFormat = $form-getWidgetSchema()-generateName($name) .
'[%s]';
$cartItemForm-getWidgetSchema()-setNameFormat($nameFormat);
else the name used in fields will be the same, then the form can't
work.
Then you have now your array of sfForm, you can get the embedded forms
of the embedded form.
$cartItemForm-getEmbeddedForms()
On May 21, 8:33 pm, Tom Haskins-Vaughan t...@templestreetmedia.com
wrote:
Hi,
I have successfully embedded a form like so:
class CartForm extends BaseCartForm
{
public function configure()
{
unset(
$this['id'],
$this['is_default'],
$this['buyer_id']
);
foreach($this-getObject()-getCartItems() as $cartItem)
{
$this-embedForm(
'cartitem_'.$cartItem-cart_id.'_'.$cartItem-harvest_id,
new CartItemForm($cartItem)
);
}
}
}
And I have managed to display it like so:
form method=post action=?php echo url_for('@my_cart') ?
tbody
?php foreach($form as $cartItemForm): ?
tr
td?php echo $cartItemForm['quantity']-renderLabel() ?/td
td?php echo $cartItemForm['quantity'] ?/td
td/td
/tr
?php endforeach; ?
/tbody
/table
input type=submit value=Update cart /
/form
But I need to access some more information about each CartItem to
display in the form, such as the Producer
($cartItem-Harvest-Producer). But in my example, it seems that
$cartItemForm is not an sfForm but a sfFormField. So how do I access the
Object of a form from a form field?
Any help much appreciated.
Thanks
Tom
--~--~-~--~~~---~--~~
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symfony users group.
To post to this group, send email to symfony-users@googlegroups.com
To unsubscribe from this group, send email to
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