specifying sort order for sort by value

2014-11-06 Thread SK
Hi,

I am using rdd.sortBy(_._2) to get an RDD sorted by value. The default order
is ascending order. How can I get it sorted  in descending order? I could
not find an option to specify the order. 

I need to get the top K elements of the list sorted in descending order. If
there is no option to get the descending order, I would like to know if
there is a way to get the last K elements of the list sorted in ascending
order.  take(k) gets the first k elements, is there an option to get the
last K elements of an RDD ?

thanks



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Re: specifying sort order for sort by value

2014-11-06 Thread Akhil Das
Yes you can sort it in desc, you simply specify a boolean value in the
second argument to the sortBy function. Default is ascending.
So it will look like:

rdd.sortBy(_._2, false)


Read more over here
http://spark.apache.org/docs/latest/api/scala/#org.apache.spark.rdd.RDD

Thanks
Best Regards

On Fri, Nov 7, 2014 at 12:20 AM, SK skrishna...@gmail.com wrote:

 Hi,

 I am using rdd.sortBy(_._2) to get an RDD sorted by value. The default
 order
 is ascending order. How can I get it sorted  in descending order? I could
 not find an option to specify the order.

 I need to get the top K elements of the list sorted in descending order. If
 there is no option to get the descending order, I would like to know if
 there is a way to get the last K elements of the list sorted in ascending
 order.  take(k) gets the first k elements, is there an option to get the
 last K elements of an RDD ?

 thanks



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Re: specifying sort order for sort by value

2014-11-06 Thread SK
Thanks. I was looking at an older RDD documentation that did not specify the
ordering option. 



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