On 9 déc, 23:56, Chris <[EMAIL PROTECTED]> wrote:
> Thanks Daniel Roseman That did the trick. I did not think to do a
> lambda
>
> > I _very_ strongly suggest you take some time learning Python. In this
> > case, the parens are actually the call operator. Not applying this
> > operator results
Thanks Daniel Roseman That did the trick. I did not think to do a
lambda
> I _very_ strongly suggest you take some time learning Python. In this
> case, the parens are actually the call operator. Not applying this
> operator results in getting a reference to the function (or whatever
>
Also, as an aside to all of that--what you're generating is in no way
guaranteed to be unique. If you really need a unique string, use a
UUID or hash of the primary key.
On Dec 9, 3:48 pm, bruno desthuilliers <[EMAIL PROTECTED]>
wrote:
> On 9 déc, 11:32, Chris <[EMAIL PROTECTED]> wrote:
>
> >
On 9 déc, 11:32, Chris <[EMAIL PROTECTED]> wrote:
> Hello,
> when django is running on a server, I want to make a call to:
> random.random(). When I make a call to this again, I can't. I think
> this related to a similar issue datetime.datetime.now() where you
> leave off the () to get a current
On Dec 9, 7:34 pm, Chris <[EMAIL PROTECTED]> wrote:
> Here is a code snippet:http://dpaste.com/97475/so basically when I
> login to the backend and try to add a couple rows. I get the same
> random id each time.
As you might realise, what's happening is that Django is evaluating
your call to
Here is a code snippet: http://dpaste.com/97475/ so basically when I
login to the backend and try to add a couple rows. I get the same
random id each time.
On Dec 9, 10:27 am, Jeff FW <[EMAIL PROTECTED]> wrote:
> Can you show me exactly what you're trying to do? That would make it
> much easier
Can you show me exactly what you're trying to do? That would make it
much easier to help you.
-Jeff
On Dec 9, 1:19 pm, Chris <[EMAIL PROTECTED]> wrote:
> I found this snippet:http://www.djangosnippets.org/snippets/814/and
> noticed that it does not work as intended do to the issue that I
>
I found this snippet: http://www.djangosnippets.org/snippets/814/ and
noticed that it does not work as intended do to the issue that I
described. I tried passing it as default instead of using the save
method but does not work and since I am not passing random to default
directly, I cannot do
Chris,
It depends on where you're calling random.random(). If you're trying
to do it in a model definition, then you're always going to have the
value it chose when it first executed the model's class definition--
when the server starts up. In that case, you should be able to pass
an argument
Hello,
when django is running on a server, I want to make a call to:
random.random(). When I make a call to this again, I can't. I think
this related to a similar issue datetime.datetime.now() where you
leave off the () to get a current date each time each time you call
it. If you dont do that,
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