On Thu, May 09, 2024 at 01:37:32PM +0800, Kewen.Lin wrote:
>
> >
> > That said, Fortran has the concept of model numbers, which
> > are set in arith.c. Does this change give the expected
> > value for ibm128? For example, with "REAL(16) X", one
> > has "DIGITS(X) = 113", which is the
Hi,
on 2024/5/9 06:01, Steve Kargl wrote:
> On Wed, May 08, 2024 at 01:27:53PM +0800, Kewen.Lin wrote:
>>
>> Previously effective target fortran_real_c_float128 never
>> passes on Power regardless of the default 128 long double
>> is ibmlongdouble or ieeelongdouble. It's due to that TF
>> mode
On Wed, May 08, 2024 at 01:27:53PM +0800, Kewen.Lin wrote:
>
> Previously effective target fortran_real_c_float128 never
> passes on Power regardless of the default 128 long double
> is ibmlongdouble or ieeelongdouble. It's due to that TF
> mode is always used for kind 16 real, which has
Hello,
Le 08/05/2024 à 07:27, Kewen.Lin a écrit :
Hi,
Previously effective target fortran_real_c_float128 never
passes on Power regardless of the default 128 long double
is ibmlongdouble or ieeelongdouble. It's due to that TF
mode is always used for kind 16 real, which has precision
127,
Hi,
Previously effective target fortran_real_c_float128 never
passes on Power regardless of the default 128 long double
is ibmlongdouble or ieeelongdouble. It's due to that TF
mode is always used for kind 16 real, which has precision
127, while the node float128_type_node for c_float128 has
128
