On Fri, 8 Jul 2011 00:06, li...@meumonus.com said:
I'm trying to use the gpg-preset-passphrase command and it keeps
failing. My thought is I'm not getting the keygrip correct. How do I
discover the keygrip for a public certificate?
With the stable 2.0 version of GnuPG the keygrip is only
When changing my secret key's passphrase, I bumped up the s2k-count to
6553600 (I just added two zeros; I don't notice any slow down when
decrypting on a Core2Duo).
How can I confirm that this count is being used?
I ran gpg --list-packets ~/.gnupg/secring.gpg, which told me a number
for protect
On Jul 8, 2011, at 10:10 AM, Chris Poole wrote:
When changing my secret key's passphrase, I bumped up the s2k-count to
6553600 (I just added two zeros; I don't notice any slow down when
decrypting on a Core2Duo).
How can I confirm that this count is being used?
I ran gpg --list-packets
On 07/08/2011 12:31 PM, David Shaw wrote:
Yes. Note that the list-packets output shows the internal packed value:
6553600 should come out to 201. The default of 65536 would encode to 96.
You might file an enhancement bug to print the decoded value in
--list-packets. We already print it
On 8 Jul 2011, at 17:31, David Shaw ds...@jabberwocky.com wrote:
Yes. Note that the list-packets output shows the internal packed value:
6553600 should come out to 201. The default of 65536 would encode to 96.
I do indeed get 201. Out of interest, how is that calculated?
I also changed the
Am Freitag, 8. Juli 2011, 20:35:57 schrieb Chris Poole:
On 8 Jul 2011, at 17:31, David Shaw ds...@jabberwocky.com wrote:
Yes. Note that the list-packets output shows the internal packed value:
6553600 should come out to 201. The default of 65536 would encode to
96.
I do indeed get 201.
On Jul 8, 2011, at 2:35 PM, Chris Poole wrote:
On 8 Jul 2011, at 17:31, David Shaw ds...@jabberwocky.com wrote:
Yes. Note that the list-packets output shows the internal packed value:
6553600 should come out to 201. The default of 65536 would encode to 96.
I do indeed get 201. Out of
Thank you.
On 8 Jul 2011, at 20:06, Hauke Laging mailinglis...@hauke-laging.de wrote:
Am Freitag, 8. Juli 2011, 20:35:57 schrieb Chris Poole:
On 8 Jul 2011, at 17:31, David Shaw ds...@jabberwocky.com wrote:
Yes. Note that the list-packets output shows the internal packed value:
6553600
Thanks for the detailed response. I've done some C programming so it's not too
alien to me.
I don't know if this would be of any real use (perhaps just for those that are
pretty sure of the slowest machine they'll be decrypting their private key on),
but a function to calculate how many rounds
