hejsgpuom62c created SPARK-27052:
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             Summary: Using PySpark udf in transform yields NULL values
                 Key: SPARK-27052
                 URL: https://issues.apache.org/jira/browse/SPARK-27052
             Project: Spark
          Issue Type: Bug
          Components: PySpark, SQL
    Affects Versions: 2.4.0
            Reporter: hejsgpuom62c


Steps to reproduce
{code:java}

from typing import Optional
from pyspark.sql.functions import expr

def f(x: Optional[int]) -> Optional[int]:
    return x + 1 if x is not None else None

spark.udf.register('f', f, "integer")

df = (spark
    .createDataFrame([(1, [1, 2, 3])], ("id", "xs"))
    .withColumn("xsinc", expr("transform(xs, x -> f(x))")))

df.show()

# +---+---------+-----+
# | id|       xs|xsinc|
# +---+---------+-----+
# |  1|[1, 2, 3]| [,,]|
# +---+---------+-----+


{code}
 

Source https://stackoverflow.com/a/53762650



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